Classify each alkyl halide as 1 °, 2°, or 3°.

Question

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Answer 1

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

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Answer 2

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

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Answer 3

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

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Answer 4

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 13

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Answer 14

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Answer 15

Conclusion

Thus the given structure is primary (1°)

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 21

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Answer 22

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Answer 23

Conclusion

Thus the given structure is tertiary (3°)

Answer 24

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 29

Answer to Problem 7.1P

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Answer 30

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry-Package(Custom), Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Answer 31

Conclusion

Thus the given structure is secondary (2°)

Answer 32

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 37

Answer to Problem 7.1P

------------➜ tertiary (3°)

Answer 38

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)