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For the circuit in Figure 7.55, the transistor parameters are
Figure 7.55 Figure for Exercise Ex 7.12
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MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
- 7.65 In the circuit in Figure P7.65, the transistor parameters are: B = 120, VBE(on) = 0.7 V, VA = 100 V, C, = 1 pF, and fr = 600 MHz. (a) Deter- mine C, and the equivalent Miller capacitance Cy. State any approxima- tions or assumptions that you make. (b) Find the upper 3 dB frequency and the midband voltage gain. +5 V Rc-4 k2 R= 33 k2 Ccz =2 AF CCi =1 uF wwwHE Rg = 2 ka 35 k2 R2= 22 ka 4 ks2 ww ww wwarrow_forwardA baseband signal has the spectrum sketched in the first image added below. The baseband signal modulates a 98 kHz carrier sine wave. Using frequency and amplitude labelling similar to that in Figure 2, sketch the spectrum of the modulated signal using a template added in image 2, for the following modulations: i-AM with the amplitude of the carrier wave being 20 V ii-DSBSC iii-SSB – the lower sideband iv-SSB – the upper sidebandarrow_forward7.65 In the circuit in Figure P7.65, the transistor parameters are: B = 120, VBE(on) = 0.7 V, VA = 100 V, C, = 1 pF, and fr = 600 MHz. (a) Deter- mine C, and the equivalent Miller capacitance CM. State any approxima- tions or assumptions that you make. (b) Find the upper 3 dB frequency and the midband voltage gain. Rc=D4 k2 R = 33 k2 C =1 uF Cc2 = 2 µF Rg = 2 k2 R = 5 ka R2 = 22 k2 Rg%3D 4 k2 Cg = 10 uF Figure P7.65 wwarrow_forward
- Q5. In the circuit in Figure P7.65, the transistor parameters are: B = 120, VBE (on) = 0.7 V, VA = 100 V, C, = 1 pF, and fr = 600 MHz. (a) Deter- mine C and the equivalent Miller capacitance CM. State any approxima- tions or assumptions that you make. (b) Find the upper 3 dB frequency and the midband voltage gain. +5 V Rc=4 k2 R = 33 k2 HH Cc2 = 2 µF CCi = 1 µF wwH Rs=2 kQ RL = 5 k2 R2 = 22 kO RE= 4 k2 CE= 10 µF Figure P7.65arrow_forwardQ2. For the scheme shown in Figure Q2, i. Draw the spectrum of the baseband signal (multiplexer output) for the multiplexer. ii. Determine the bandwidth of the baseband signal (multiplexer output) for the multiplexer. iii. Determine the minimum transmission bandwidth of the multiplexer. Explain, briefly, the modification needed for the multiplexer in the figure to achieve this bandwidth. 3 kHz cos 10,000nt Bascband signal cos? 1000nt Σ cos 22,000rt 4 kHz cos 36,000nt Figure Q2arrow_forwardModify this circuit to extend the upper frequency limit to greater than 15 MHz. You may change the topology (i.e. configuration), but not the power supply voltage or collector bias current. The circuit voltage gain must be 46dB +/- 1 dB. Provide simulation results to show AC frequency responses of both circuits on the same plot, and annotate the 3dB upper frequency limit on both traces. Use typical ẞ values from the data sheet for the simulation. You may assume that 1% resistors are available in values below 100. The circuit must adhere to Standard Bias techniques. V4 Rser=0 SINE(0 0.02 10k) AC 1 VCC ୯ V2 +15V Cin1 1μ -VCC VCC R4 Rc1 147k 7k Q3 2N3904 R7 R6 9.09 20.5k Ce1 Re1 1.00k 10p Outarrow_forward
- A bipolar transistor has parameters B, = 150, C, = 2 pF and C = 0.3 pF and is biased at lco = 0.5 mA. Determine the beta cut-off frequency.arrow_forward7.26. The sampling theorem, as we have derived it, states that a signal x(1) must be sam- pled at a rate greater than its bandwidth (or equivalently, a rate greater than twice its highest frequency). This implies that if x(1) has a spectrum as indicated in Figure P7.26(a) then x(1) must be sampled at a rate greater than 2002. However, since the signal has most of its energy concentrated in a narrow band, it would seem reason- able to expect that a sampling rate lower than twice the highest frequency could be used. A signal whose energy is concentrated in a frequency band is often referred to as a bandpass signal. There are a variety of techniques for sampling such signals, generally referred to as bandpass-sampling techniques. x(t) X(jw) MA @₁ W₂ (a) -W₂ -W₁ p(t) = Σ 8(t-nT) Io. Xp (t) H(jw) 1 -Wo n Wa p(t) H(jw) A+ (b) 3° W wp w x, (t) Figure P7.26arrow_forwardQ6/ In FM system the modulating signal is 2.4v and 500HZ, the peak frequency deviation is 4.8KHZ. Now if modulating signal voltage becomes 7.2v what is the new frequency deviation? If the modulating voltage is raised to 10v while frequency is dropped to 200HZ, what is the frequency deviation? Find the modulation index, bandwidth, and no. of sidebands in each case.arrow_forward
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