Consider the common−base circuit in Figure 7.64. The transistor parameters are
Figure 7.64 Figure for Exercise Ex 7.14
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MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
- Describe the combined effect of the RC circuits for higher frequency response in a BJT & FETamplifier. the subject : Analogue Electronics IIarrow_forwardProblem 7.133(a): For the circuit shown below, let R1 = 106 kN, Rsig = 69 N, and RL Rsig. Assume that %3D 13 kN. Find the value of the bias current I in mA that results in Rin the source provides a small signal vsie and that B = 100. H RL R1 Rsig Ria 8arrow_forwardQ2. Consider the circuit shown in Figure P7.15. The transistor has parameters B = 120 and VA collector-emitter voltage is VCEO = 1.25 V. (a) Determine Rc, (b) find Ico, and (c) determine the maximum gain. = ∞. The circuit bandwidth is 800 MHz and the quiescent Vcc= 2.5 V RC CL = 0.08 pF Figure P7.15arrow_forward
- 3. State the conditions of the emitter-base and the collector-base junctions when the BJT operates in the cut-off, saturation and active modes. 4. Explain why in the ac analysis at middle frequency range, all external capacitors are assumed to be a short-circuit.arrow_forwardVs=100 mV peak-to-peak, 1 kHz sine signal, Kn=0.4mA/v^2 ,Vt=1V , λ=0.01V^-1 Make the DC analysis of the above given mosfet amplifier circuit. Simulation to tableWrite down the measured values and mathematical calculation results. (The valueswith the units.)DC Parameters ,Measured value ,Calculated ValueVGETCVGSVDVDSIDb. Draw the small signal model for the AC analysis of the circuit. Find the gm, ro, Av values.c. Show the Vs input signal and the Vo output signal of the circuit on the oscilloscope. Volt/div of channels andSpecify time/div values.arrow_forward2) For a PM modulator with sensitivity K=2.5 rad/V and modulating signal vm(t) = 4sin(212000t), (a) determine the peak phase deviation. (b) How much phase deviation is produced for a modulating signal with twice the amplitude?arrow_forward
- The modulating index of an AM-signal is reduced from 0.8 to 0.5. The ratio of the total power in the new modulated signal to that of the original signal will nearly bearrow_forwardQ2. For the scheme shown in Figure Q2, i. Draw the spectrum of the baseband signal (multiplexer output) for the multiplexer. ii. Determine the bandwidth of the baseband signal (multiplexer output) for the multiplexer. iii. Determine the minimum transmission bandwidth of the multiplexer. Explain, briefly, the modification needed for the multiplexer in the figure to achieve this bandwidth. 3 kHz cos 10,000nt Bascband signal cos? 1000nt Σ cos 22,000rt 4 kHz cos 36,000nt Figure Q2arrow_forwardma=Acmax-Acmin/Acmax+Acmin for the modulated signal (AM) ,ma = 0.25;Calculate Acmax, Acmin and efficiency value.arrow_forward
- (a) What collector current is required for a bipolar transistor to achieve a transconductance of 40 mS? (b) Repeat for a transconductance of 200μS. (c) Repeat for a transconductance of 40 μS.arrow_forwardProblem 01: Draw a real-life MOSFET circuit(Ac model) and derive the circuit in that circuit to find operating region, circuit biasing, Ac model, and frequency response curve.arrow_forwardThis problem is AC analysis problem. DC analysis is not needed to answer the question. A) If we assume that the peak voltage of Vbe must be less than 10 mV to avoid small signal violations determine the value of Rsig if Vi has a peak amplitude of 1 V and Is = 1mA. Hint: Don't forget r!! Answer: Rsig =. B) If you did the DC analysis on this problem and calculated Vc = 50 mV and Vs = -100 mV what is the maximum amplitude of the output voltage while the circuit stays in active mode. Answer: Vo,max =, When you "verify" a mode of operation you will need to calculate all three voltages (Vc, Ve, VE for BJTS and VG, Vs, Vp for MOSFETS) and show the correct two conditions are satisfied. Assume Capacitors acts like open circuits at DC and short circuits for AC. > Assume the following: 5V o Beta = 100 O VBE = 0.7 o V: (Thermal) = 26 mV o Vr (Threshold) = 2V O VA = - o For MOSFET saturation mode: assume: lp = K(VGs-Vr)? (Assume K = 10 mA/V²). 5kn C2 01 C1 Rsig 1kn 10k Vi IIs :C3 1mA -5Varrow_forward
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