Biochemistry, The Molecular Basis of Life, 6th Edition
6th Edition
ISBN: 9780190259204
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 7, Problem 31FB
Summary Introduction
To review:
The blank space in the statement, “_____ are non-superimposable, non-mirror-image stereoisomers.”
Introduction:
The molecules (or stereoisomers) that are mirror images of each other, but are not identical, and are non-superimposable, are known as enantiomers. When similar structural (chemical structure) features are present in two different compound, shere is a possibility of them beingnon-superimposable structures.
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draw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been included. Draw the structure for glycine, alanine, valine, isoleucine, methionine, proline, phenylalanine, tryptophan, serine, threonine, asparagine, glutamine, lysine, arginine, aspartic acid, glutamic acid, histidine, tyrosine, cysteine
draw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been included
draw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been included
Chapter 7 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
Ch. 7 - Prob. 1QCh. 7 - Prob. 2QCh. 7 - Prob. 3QCh. 7 - Prob. 4QCh. 7 - Prob. 5QCh. 7 - Prob. 6QCh. 7 - Prob. 7QCh. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQ
Ch. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQCh. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 20RQCh. 7 - Prob. 21RQCh. 7 - Prob. 22RQCh. 7 - Prob. 23RQCh. 7 - Prob. 24RQCh. 7 - Prob. 25RQCh. 7 - Prob. 26RQCh. 7 - Prob. 27RQCh. 7 - Prob. 28FBCh. 7 - Prob. 29FBCh. 7 - Prob. 30FBCh. 7 - Prob. 31FBCh. 7 - Prob. 32FBCh. 7 - Prob. 33FBCh. 7 - Prob. 34FBCh. 7 - Prob. 35FBCh. 7 - Prob. 36FBCh. 7 - Prob. 37FBCh. 7 - Prob. 38SACh. 7 - Prob. 39SACh. 7 - Prob. 40SACh. 7 - Prob. 41SACh. 7 - Prob. 42SACh. 7 - Prob. 43TQCh. 7 - Prob. 44TQCh. 7 - Prob. 45TQCh. 7 - Prob. 46TQCh. 7 - Prob. 47TQCh. 7 - Prob. 48TQCh. 7 - Prob. 49TQCh. 7 - Prob. 50TQCh. 7 - Prob. 51TQCh. 7 - Prob. 52TQCh. 7 - Prob. 53TQCh. 7 - Prob. 54TQCh. 7 - Prob. 55TQCh. 7 - Prob. 56TQCh. 7 - Prob. 57TQCh. 7 - Prob. 58TQCh. 7 - Prob. 59TQCh. 7 - Prob. 60TQCh. 7 - Prob. 61TQCh. 7 - Prob. 62TQCh. 7 - Prob. 63TQCh. 7 - Prob. 64TQCh. 7 - Prob. 65TQCh. 7 - Prob. 66TQCh. 7 - Prob. 67TQCh. 7 - Prob. 68TQCh. 7 - Prob. 69TQCh. 7 - Prob. 70TQ
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- for each pair of biomolecules, identify the type of reaction (oxidation-reduction, hydrolysis, isomerization, group transfer, or nternal rearrangement) required to convert the first molecule to the second. In each case, indicate the general type of enzyme and cofactor(s) c reactants required, and any other products that would result. R-CH-CH-CH-C-S-COA A(n) A(n) A(n) A(n) Palmitoyl-CoA R-CH-CH=CH-C-S-CoA ° trans-A-Enoyl-CoA reaction converts palmitoyl-CoA to trans-A2-enoyl-CoA. This reaction requires and also produces Coo HN-C-H CH₂ CH₂ CH CH CH, CH, L-Leucine CH, CH, D-Leucine 8/6881 COO HÌNH: reaction converts L-leucine to D-leucine. This reaction is catalyzed by a(n) H-C-OH H-C-OH C=0 HO-C-H HO-C-H H-C-OH H-C-OH H-C-OH CH,OH Glucose H-C-OH CH,OH Fructose OH OH OH CH-C-CH₂ reaction converts glucose to fructose. This reaction is catalyzed by a(n) OH OH OPO I CH-C-CH H Glycerol Glycerol 3-phosphate H reaction converts glycerol to glycerol 3-phosphate. This reaction requires H,N- H,N H…arrow_forwardAfter adding a small amount of ATP labeled with radioactive phosphorus in the terminal position, [7-32P]ATP, to a yeast extract, a researcher finds about half of the 32P activity in P; within a few minutes, but the concentration of ATP remains unchanged. She then carries out the same experiment using ATP labeled with 32P in the central position, [ẞ-³2P]ATP, but the 32P does not appear in P; within such a short time. Which statements explain these results? Yeast cells reincorporate P; released from [ß-³2P]ATP into ATP more quickly than P¡ released from [y-³2P]ATP. Only the terminal (y) phosphorous atom acts as an electrophilic target for nucleophilic attack. The terminal (y) phosphoryl group undergoes a more rapid turnover than the central (B) phosphate group. Yeast cells maintain ATP levels by regulating the synthesis and breakdown of ATP. Correct Answerarrow_forwardCompare the structure of the nucleoside triphosphate CTP with the structure of ATP. NH₂ 0- 0- 0- ·P—O—P—O—P—O—CH₂ H H H H OH OH Cytidine triphosphate (CTP) Consider the reaction: ATP + CDP ADP + CTP NH 0- 0- 0- ¯0— P—O— P—O—P-O-CH₂ H Η о H H OH OH Adenosine triphosphate (ATP) NH₂ Now predict the approximate K'eq for this reaction. Now predict the approximate AG for this reaction. Narrow_forward
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