Chapter 6.8, Problem 13E

To determine

To find : the probability that both spinner stop on the same numberwhen each spinner spin once.

Answer to Problem 13E

The probability that both spinner stops on the same numberis $\frac{\text{1}}{5}$

Explanation of Solution

Given information :

Consider, the information provided in the question,

The spinner B is divided into 5 equal parts namely 1, 2, 3, 4 and 5 and spinner B is divided into 4 equal parts namely 1, 2, 3, and 4.

Calculation :

Since, spinner A is divided into 5 parts and spinner B is divided into 4 parts. Therefore, total number of possible outcome is $5\times 4=20$ .

Now, to stop on same number the spinner should stop either on 1, 2, 3, or 4. Thus, number of favourable outcome is 4. Therefore, the probability that both spinner stops on the same number is

  $\begin{array}{l}P\left(\text{Stops on same number}\right)=\frac{\text{Number of favaourable outcome}}{\text{Total number of outcome}}\\ P\left(\text{Stops on same number}\right)=\frac{\text{4}}{20}\\ P\left(\text{Stops on same number}\right)=\frac{\text{1}}{5}\end{array}$

Hence,

The probability that both spinner stops on the same number is $\frac{\text{1}}{5}$ .