Chapter 6, Problem 4CT

To determine

To write : the equivalent rate.

Answer to Problem 4CT

The equivalent rate is $\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\text{? dollars}}{1\text{ oz}}$ is $\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\$0.35}{1\text{ oz}}$

Explanation of Solution

Given information :

Consider, the proportion

  $\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\text{? dollars}}{1\text{ oz}}$

Calculation:

To convert from dollars per pound to dollars per ounce, multiply the rate by a conversion factor. There are 16 ounce in one pound so, $\frac{\text{1 lb}}{16\text{ ounce}}=1$

Therefore,

  $\begin{array}{l}\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\text{\$5}\text{.60}÷\text{16}}{1\text{ oz}}\left[\text{divide by conversion factor}\right]\\ \frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\$0.35}{1\text{ oz}}\end{array}$

Hence,The equivalent rate of the proportion $\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\text{? dollars}}{1\text{ oz}}$ is $\frac{\text{\$5}\text{.60}}{\text{1lb}}=\frac{\$0.35}{1\text{ oz}}$