Chapter 6, Problem 2CT

To determine

To order : the ratio from least to greatest

Answer to Problem 2CT

The ratio from least to greatest is $\text{9 }to\text{ 4}0<37:20<\frac{53}{25}<\frac{64}{25}<59:20$

Explanation of Solution

Given information :

Consider, the ratio provided in the question

Calculation:

Convert all the ratio in fraction form

  $\begin{array}{l}\frac{64}{25}=\frac{64\times 8}{25\times 8}=\frac{512}{200}\\ 9to40=\frac{9}{40}=\frac{9\times 5}{40\times 5}=\frac{45}{200}\\ 59:20=\frac{59}{20}=\frac{59\times 10}{20\times 10}=\frac{590}{200}\\ \frac{53}{25}=\frac{53\times 8}{25\times 8}=\frac{424}{200}\\ 37:20=\frac{37}{20}=\frac{37\times 10}{20\times 10}=\frac{370}{200}\\ \text{9 }to\text{ 4}0<37:20<\frac{53}{25}<\frac{64}{25}<59:20\end{array}$

From the above explanation, it can be observed that the order of the ratio from least to greatest is: $\text{9 }to\text{ 4}0<37:20<\frac{53}{25}<\frac{64}{25}<59:20$

Hence, the ratio from least to greatest is $\text{9 }to\text{ 4}0<37:20<\frac{53}{25}<\frac{64}{25}<59:20$