Chapter 6.3, Problem 3C

To determine

To find: whether the ratios form a proportion.

Answer to Problem 3C

  $\frac{6}{11},\frac{9}{16}$ are not in proportion

Explanation of Solution

Given information: consider the ratios provided in the question,

  $\frac{6}{11},\frac{9}{16}$

Calculation:

Use cross products of the provided ratio, TO-DETERMINE if the they are in proportion,

  $\begin{array}{l}\frac{6}{11}=\frac{9}{16}\\ 6·16=9·11\\ 96\ne 99\end{array}$

Hence, $\frac{6}{11},\frac{9}{16}$ are not in proportion.