Chapter 6, Problem 1CT

To determine

To order : the ratio from least to greatest

Answer to Problem 1CT

The ratio from least to greatest is $17to20<\frac{5}{4}<13:10<\frac{33}{20}<51to25$

Explanation of Solution

Given information :

Consider, the ratio provided in the question

Calculation:

Convert all the ratio in fraction form

  $\begin{array}{l}17to20=\frac{17}{20}=\frac{17\times 5}{20\times 5}=\frac{85}{100}\\ \frac{5}{4}=\frac{5\times 25}{4\times 25}=\frac{125}{100}\\ 13:10=\frac{13}{10}=\frac{13\times 10}{10\times 10}=\frac{130}{100}\\ \frac{33}{20}=\frac{33\times 5}{20\times 5}=\frac{165}{100}\\ 51to25=\frac{51}{25}=\frac{51\times 4}{25\times 4}=\frac{204}{100}\\ 17to20<\frac{5}{4}<13:10<\frac{33}{20}<51to25\end{array}$

From the above explanation, it can be observed that the order of the ratio from least to greatest is: $17to20<\frac{5}{4}<13:10<\frac{33}{20}<51to25$

Hence, the ratio from least to greatest is $17to20<\frac{5}{4}<13:10<\frac{33}{20}<51to25$