Chapter 6.7, Problem 9E

To determine

To find : The spinner is divided into 8 equal parts. What are the oddsagainst stopping on a 1 or a 2.

Answer to Problem 9E

Odds against stopping on a 1 or a 2 is $\frac{\text{1}}{\text{3}}$ .

Explanation of Solution

Given information :

Consider, the information provided in the question,

The spinner is divided into 8 equal parts and it stops on a 1 or a 2.

Calculation :

Here, there are 2 unfavourable outcomes (1, 2) and $8-2=6$ favourable outcomes.

Odd against stopping on 1 or 2 is:

  $\begin{array}{l}\text{Odds against}=\frac{\text{Number of unfavouarable outcome}}{\text{Number of favorable outcome}}\\ \text{Odds against}=\frac{\text{2}}{\text{6}}\\ \text{Odds against}=\frac{\text{1}}{\text{3}}\end{array}$

Hence,

Odds against stopping on a 1 or a 2 is $\frac{\text{1}}{\text{3}}$ .