Chapter 6, Problem 3CT

To determine

To write : the equivalent rate.

Answer to Problem 3CT

The equivalent rate is $\frac{\text{18ft}}{\text{1sec}}=\frac{\text{?ft}}{1\min }$ is $\frac{\text{18ft}}{\text{1sec}}=\frac{\text{1080ft}}{1\min }$

Explanation of Solution

Given information :

Consider, the proportion

  $\frac{\text{18ft}}{\text{1sec}}=\frac{\text{?ft}}{1\min }$

Calculation:

To convert from feet per second to feet per minute, multiply the rate by a conversion factor. There are 60 second in one minute so, $\frac{\text{1 minute}}{\text{60 second}}=1$

Therefore,

  $\begin{array}{l}\frac{\text{18ft}}{\text{1sec}}=\frac{18\cdot 60}{1\min }\left[\text{multiply by conversion factor}\right]\\ \frac{\text{18ft}}{\text{1sec}}=\frac{\text{1080ft}}{1\min }\end{array}$

Hence,The equivalent rate of the proportion $\frac{\text{18ft}}{\text{1sec}}=\frac{\text{?ft}}{1\min }$ is $\frac{\text{18ft}}{\text{1sec}}=\frac{\text{1080ft}}{1\min }$