Explanation The following figure gives the free body diagram of the force exerted on the block E . Write the expression to find the length of B F . B F = a sin15 ° (I) Write the expression for the sin β in terms of B F . sin β = B F B D (II) Write the equation to find the moment of force. M = F a Here, F is the force acting and a is the perpendicular distance from the force to the point about which the moment is calculated. Write the equation to find the total moment about the point A . Σ M A = Σ ( F a ) Write the equations for equilibrium for the free body diagram in figure 1. Σ M A = 0 (III) Here, M A is the torque about the point A . Write the expression for the horizontal force exerted on the block. ( F B D ) x = F B D cos β (IV) Conclusion: Substitute 8 in . for a in equation (I). B F = ( 8 in . ) sin15 ° = 2.0706 in . Substitute 2.0706 in . for B F and 6 in . for B D in equation (II) and solve it to find β . sin β = 2

Vector Mechanics for Engineers: Statics, 11th Edition

11th Edition

ISBN: 9780077687304

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek

Publisher: McGraw-Hill Education

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Chapter 6.4, Problem 6.124P

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The horizontal force exerted on the block E.

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Chapter 6.4, Problem 6.123P

Chapter 6.4, Problem 6.125P

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Chapter 6 Solutions

Vector Mechanics for Engineers: Statics, 11th Edition

Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.2P Ch. 6.1 - Prob. 6.3P Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Using the method of joints, determine the force in...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.8P Ch. 6.1 - 6.9 and 6.10 Determine the force in each member of...Ch. 6.1 - 6.9 and 6.10 Determine the force in each member of...

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The horizontal force exerted on the block E .

Solution Summary: The following figure gives the free body diagram of the force exerted on the block E.

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