Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF( s ) (The sublimation energy for Li( s ) is +159.4 kJ/mol, the E i for Li( g ) is 520 kJ/mol, the E ea for F( g ) is − 328 kJ/mol , and the bond dissociation energy of F 2 ( g ) is + 158 kJ/mol .] (b) CaF 2 ( s ) [The sublimation energy for Ca( s ) is + 178.2 kJ/mol, E i1 = + 589 . 8 kJ/mol , and E i2 = + 1145 kJ/mol .]
Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF( s ) (The sublimation energy for Li( s ) is +159.4 kJ/mol, the E i for Li( g ) is 520 kJ/mol, the E ea for F( g ) is − 328 kJ/mol , and the bond dissociation energy of F 2 ( g ) is + 158 kJ/mol .] (b) CaF 2 ( s ) [The sublimation energy for Ca( s ) is + 178.2 kJ/mol, E i1 = + 589 . 8 kJ/mol , and E i2 = + 1145 kJ/mol .]
Solution Summary: The author explains the Born-Haber cycle of ionic solids from its constituent elements.
Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF(s) (The sublimation energy for Li(s) is +159.4 kJ/mol, the
E
i
for Li(g) is 520 kJ/mol, the
E
ea
for F(g) is
−
328 kJ/mol
, and the bond dissociation energy of
F
2
(
g
)
is
+
158 kJ/mol
.] (b) CaF2(s) [The sublimation energy for Ca(s) is + 178.2 kJ/mol,
E
i1
=
+
589
.
8 kJ/mol
, and
E
i2
=
+
1145 kJ/mol
.]
Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
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