(a) Interpretation: The explanation corresponding to the given statement, “the homolysis of the O − H bond in phenol requires considerably less energy than homolysis of the O − H bond in ethanol” is to be stated. Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron. Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Question

Want to see the full answer?

Answer 1

Question

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

7. The reaction of methoxide anion with bromoethane to yield the ether ethyl methyl ether and the bromide anon (Br-) is an excellent example of a general reaction type called Sy2 (substitution nucleophilic bimolecular): CH,0+ CH,СH-Br a CH3-0-CH,СH; + Br- a. Change in enthalpy is -103 kJ/mol; the change in entropy is + 0.025 kJ/mol-K. Calculate DG at 300K. b. Is the reaction endergonic or exergonic? c. Is the reaction endothermic or exothermic? d. Use curved arrows to show the complete mechanism. Reaction of 2-methyl-1-butene with H-Cl could yield TWO alkyl chloride products. Draw and name 8. them.

solve 78b

what will the products of the reaction?

Answer 2

Question

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Answer 6

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Answer 7

Chapter 6, Problem 6.59P

Interpretation Introduction

(a)

Interpretation: The explanation corresponding to the given statement, “the homolysis of the O−H bond in phenol requires considerably less energy than homolysis of the O−H bond in ethanol” is to be stated.

Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.

Resonance is the delocalisation of π electrons in conjugated position which leads to the formation of more than one structure. These structures are known as resonance structures

Answer 8

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Answer 9

Interpretation Introduction

(b)

Interpretation: The reason for the shorter C−O bond in phenol than the C−O bond in ethanol is to be stated.

Concept introduction: The bond length is inversely related to the bond strength. Bond length is defined as the distance between the centers of the nuclei of two bonded atoms in a molecule. It is determined by bond order. The increasing s character increases the interaction between atoms, which results in shorter bond length.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 6 - Problem 6.1 Classify each transformation as...Ch. 6 - Prob. 6.2P Ch. 6 - Problem 6.3 By taking into account...Ch. 6 - Problem 6.4 Use curved arrows to show the movement...Ch. 6 - Problem 6.5 Follow the curved arrows and draw the...Ch. 6 - Prob. 6.6P Ch. 6 - Problem 6.7 Use the values in Table 6.2 to...Ch. 6 - Prob. 6.8P Ch. 6 - aWhich Keq corresponds to a negative value of G,...Ch. 6 - Given each of the following values, is the...

Solution Summary: The author explains that the formation of carbocation, carbanion and free radical occurs due to the heterolysis process.

Want to see the full answer?

Chapter 6 Solutions