(a)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy is represented by
If the
Answer to Problem 6.38P
The formation of starting material is favored at the given value of
Explanation of Solution
Given
The value of
The given value of
(a) The formation of starting material is favored at the given value of
(b)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given:
The value of
The given value of
The formation of the product is favored at the given value of
(c)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting material is favoredat the given values of
Explanation of Solution
Given
The values of
The given values of
The formation of the starting material is favouredat the given values of
(d)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy is represented by
If the
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given
The value of
The given value of
The formation of the product is favored at the given value of
(e)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting materialis favored at the given value of
Explanation of Solution
Given
The value of
The given value of
The formation of the starting material is favored at the given value of
(f)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given
The value of
For the spontaneous reaction, the value of
The formation of the product is favored at the given value of
(g)
Interpretation: The starting material or product which isfavored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting material is favored at the given value of
Explanation of Solution
Given
The value of
The value of
The formation of the starting material is favored at the given value of
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Chapter 6 Solutions
ORGANIC CHEMISTRY
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- Gg.79.arrow_forwardGiven the Ke value for the following reaction at a particular temperature: SO₂ (g) + O₂ (g) = SO3 (9) K₂ = 1.24 What is the value of Ke for the new equilibrium below at the same temperature? 2 SO3 (g) 2 SO₂ (g) + O₂ (g) T 0.367 O 1.61 0.650 O 0.115arrow_forwardConsider the following system at equilibrium: CH4(g) + H2O(g) D CO (g) + 3H2 (g) ΔH° = +206 kJ. Which of the following changes will shift the equilibrium to the left? decreasing the pressure adding a catalyst adding methane increasing the temperature decreasing the volumearrow_forward
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