
(a)
Interpretation:
The product for given reaction should be determined.
Concept Introduction:
Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and a
If a carbonyl group is bonded to two alkyl groups, it is called as a
Conversion of terminal
(b)
Interpretation:
The product for given reaction should be determined.
Concept Introduction:
Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and a
If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.
Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.
(c)
Interpretation:
The product for given reaction should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
(d)
Interpretation:
The product for given reaction should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for deprotonation and one of the common reagents is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

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Chapter 6 Solutions
Essential Organic Chemistry (3rd Edition)
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- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
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