Explanation Write the expression for the mass balance. m i n − m o u t = Δ m Here, mass of the refrigerant R-134a entering into the system is m i n , the mass of refrigerant R-134a leaving out of the system is m o u t and change in mass is Δ m . Rewrite the mass balance equation for the mixing in chamber. m ˙ 1 + m ˙ 2 = m ˙ 3 (I) Here, mass flow rate of liquid refrigerant R-134a entering into the chamber is m ˙ 1 , mass flow rate of superheated steam entering into the chamber is m ˙ 2 and mass flow rate of refrigerant R-134a leaving out the chamber is m ˙ 3 . Write the energy rate balance equation for a control volume. E ˙ in − E ˙ out = d E ˙ system / d t = 0 ( For steady state ) Here, total energy rate at inlet is E ˙ in , total energy rate at outlet is E ˙ out and change in net energy rate is d E ˙ system / d t . Rewrite the energy balance Equation for the mixing of refrigerant R-134a in chamber neglecting the potential and kinetic energies. E ˙ in = E ˙ out m ˙ 1 h 1 + m ˙ 2 h 2 = m ˙ 3 h 3 (II) Here, specific enthalpy of liquid refrigerant R-134a entering into the chamber is h 1 , the specific enthalpy of the superheated steam entering into the chamber is h 2 , and specific enthalpy of refrigerant R-134a leaving out of chamber is h 3 . Write the formula to calculate the specific enthalpy of refrigerant R-134a ( h ) from tables. h = h f + x ( h g − h f ) (III) Here, specific enthalpy of saturated liquid is h f , specific enthalpy of saturated vapor is h g and dryness fraction of refrigerant R-134a is x . Conclusion: Refer Table A-11, “Saturated refrigerant R-134a - Temperature”, obtain the specific enthalpy ( h 1 ) of liquid refrigerant R-134a at temperature ( T 1 ) of 20 ° C . h 1 = h f = 79 .32 kJ / kg . Refer Table A-13, “Superheated refrigerant R-134a”, obtain the specific enthalpy ( h 2 ) of superheated steam at pressure ( P 2 ) of 1 MPa and temperature ( T 2 ) of 80 ° C as 314 .27 kJ / kg . Rewrite the energy balance Equation (II). m ˙ 1 h 1 + m ˙ 2 h 2 = m ˙ 3 h 3 Substitute Equation (I) for m ˙ 3

8th Edition

ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

See similar textbooks

Videos

Question

Chapter 5.5, Problem 74P

To determine

The temperature of the exiting stream and the quality of exiting stream.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5.5, Problem 73P

Chapter 5.5, Problem 76P

Students have asked these similar questions

got wrong answers help please

A crate weighs 530 lb and is hung by three ropes attached to a steel ring at A such that the top surface is parallel to the xy plane. Point A is located at a height of h = 42 in above the top of the crate directly over the geometric center of the top surface. Use the dimensions given in the table below to determine the tension in each of the three ropes. 2013 Michael Swanbom cc00 BY NC SA ↑ Z C b B У a D Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 30 in b 43 in 4.5 in The tension in rope AB is 383 x lb The tension in rope AC is 156 x lb The tension in rope AD is 156 x lb

A block of mass m hangs from the end of bar AB that is 7.2 meters long and connected to the wall in the xz plane. The bar is supported at A by a ball joint such that it carries only a compressive force along its axis. The bar is supported at end B by cables BD and BC that connect to the xz plane at points C and D respectively with coordinates given in the figure. Cable BD is elastic and can be modeled as a linear spring with a spring constant k = 400 N/m and unstretched length of 6.34 meters. Determine the mass m, the compressive force in beam AB and the tension force in cable BC. Z C D (c, 0, d) (a, 0, b) A B y f m cc 10 BY NC SA 2016 Eric Davishahl x Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 8.1 m b 3.3 m с 2.7 m d 3.9 m e 2 m f 5.4 m The mass of the block is 68.8 The compressive force in bar AB is 364 × kg. × N. The tension in cable BC is 393 × N.

Chapter 5 Solutions

Thermodynamics: An Engineering Approach

Ch. 5.5 - Prob. 1P Ch. 5.5 - Define mass and volume flow rates. How are they...Ch. 5.5 - Does the amount of mass entering a control volume...Ch. 5.5 - Consider a device with one inlet and one outlet....Ch. 5.5 - The ventilating fan of the bathroom of a building...Ch. 5.5 - 5–6E Air whose density is 0.078 lbm/ft3 enters the...Ch. 5.5 - 5–7 Air enters a 28-cm diameter pipe steadily at...Ch. 5.5 - A steady-flow compressor is used to compress...Ch. 5.5 - A 2-m3 rigid tank initially contains air whose...Ch. 5.5 - 5–10 A cyclone separator like that in Fig. P5–10...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.