For the reaction 3O 2 ( g ) ⇌ 2O 3 ( g ) The equilibrium constant at 1600 K is 0.235 . (a) If initially, 1.00 atm of O 2 were introduced into a chamber at 1600 K , what are the partial pressures present at equilibrium? ( Hint: you will have to solve a cubic equation. There are cubic equation solvers available on the internet.) (b) In a second experiment, 1.00 atm of O 2 is introduced in a chamber at 1600 K , along with 0.50 atm of Kr . Now, what are the partial pressures present at equilibrium?
For the reaction 3O 2 ( g ) ⇌ 2O 3 ( g ) The equilibrium constant at 1600 K is 0.235 . (a) If initially, 1.00 atm of O 2 were introduced into a chamber at 1600 K , what are the partial pressures present at equilibrium? ( Hint: you will have to solve a cubic equation. There are cubic equation solvers available on the internet.) (b) In a second experiment, 1.00 atm of O 2 is introduced in a chamber at 1600 K , along with 0.50 atm of Kr . Now, what are the partial pressures present at equilibrium?
Solution Summary: The author explains the equilibrium partial pressures of species in the given reaction are to be calculated.
The equilibrium constant at
1600
K
is
0.235
. (a) If initially,
1.00
atm
of
O
2
were introduced into a chamber at
1600
K
, what are the partial pressures present at equilibrium? (Hint: you will have to solve a cubic equation. There are cubic equation solvers available on the internet.) (b) In a second experiment,
1.00
atm
of
O
2
is introduced in a chamber at
1600
K
, along with
0.50
atm
of
Kr
. Now, what are the partial pressures present at equilibrium?
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell