Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
2nd Edition
ISBN: 9780393655551
Author: KARTY, Joel
Publisher: W. W. Norton & Company
bartleby

Concept explainers

Question
Book Icon
Chapter 5, Problem 5.34P
Interpretation Introduction

(a)

Interpretation:

The Fischer projection structure of L-mannose is to be drawn.

Concept introduction:

Fischer projections are used to represent the configurations about asymmetric carbons in a molecule. Perpendicular intersecting lines represent a carbon atom from the longest carbon chain. The bonds between carbon atoms from this chain are represented by vertical lines. Bonds to the two groups attached to each carbon are represented by horizontal lines. Horizontal bonds point toward the viewer whereas vertical bonds point away from the viewer.

The Fischer projections of the isomers of glyceraldehyde gives, the D/L system of classification of carbohydrates. If the location of the OH group on the highest numbered asymmetric carbon matches with that in D-glyceraldehyde on the right, the carbohydrate is designated D. If it matches with the location of the OH group in L-glyceraldehyde on the left, the carbohydrate is designated L.

D and L sugars are isomers of each other.

Epimers are isomers that differ in configuration at only one asymmetric carbon.

Interpretation Introduction

(b)

Interpretation:

The Fischer projection structure of L-arabinose is to be drawn.

Concept introduction:

Fischer projections are used to represent the configurations about asymmetric carbons in a molecule. Perpendicular intersecting lines represent a carbon atom from the longest carbon chain. The bonds between carbon atoms from this chain are represented by vertical lines. Bonds to the two groups attached to each carbon are represented by horizontal lines. Horizontal bonds point toward the viewer whereas vertical bonds point away from the viewer.

The Fischer projections of the isomers of glyceraldehyde gives, the D/L system of classification of carbohydrates. If the location of the OH group on the highest numbered asymmetric carbon matches with that in D-glyceraldehyde on the right, the carbohydrate is designated D. If it matches with the location of the OH group in L-glyceraldehyde on the left, the carbohydrate is designated L.

D and L sugars are isomers of each other.

Epimers are isomers that differ in configuration at only one asymmetric carbon.

Interpretation Introduction

(c)

Interpretation:

The Fischer projection of L-threose is to be drawn

Concept introduction:

Fischer projections are used to represent the configurations about asymmetric carbons in a molecule. Perpendicular intersecting lines represent a carbon atom from the longest carbon chain. The bonds between carbon atoms from this chain are represented by vertical lines. Bonds to the two groups attached to each carbon are represented by horizontal lines. Horizontal bonds point toward the viewer whereas vertical bonds point away from the viewer.

The Fischer projections of the isomers of glyceraldehyde gives, the D/L system of classification of carbohydrates. If the location of the OH group on the highest numbered asymmetric carbon matches with that in D-glyceraldehyde on the right, the carbohydrate is designated D. If it matches with the location of the OH group in L-glyceraldehyde on the left, the carbohydrate is designated L.

D and L sugars are isomers of each other.

Epimers are isomers that differ in configuration at only one asymmetric carbon.

Interpretation Introduction

(d)

Interpretation:

The Fischer projection structure of C2 epimer of L-arabinose is to be drawn.

Concept introduction:

The pair of stereoisomers is nothing but Epimers. Epimers are isomers that shows difference in the configuration at only one chiral centre.

Blurred answer
Students have asked these similar questions
Don't used hand raiting and don't used Ai solution
2. 200 LOD For an unknown compound with a molecular ion of 101 m/z: a. Use the molecular ion to propose at least two molecular formulas. (show your work) b. What is the DU for each of your possible formulas? (show your work) C. Solve the structure and assign each of the following spectra. 8 6 4 2 (ppm) 150 100 50 ō (ppm) 4000 3000 2000 1500 1000 500 HAVENUMBERI-11
Complete the spectroscopy with structure

Chapter 5 Solutions

Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)

Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.48PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. 5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.1YTCh. 5 - Prob. 5.2YTCh. 5 - Prob. 5.3YTCh. 5 - Prob. 5.4YTCh. 5 - Prob. 5.5YTCh. 5 - Prob. 5.6YTCh. 5 - Prob. 5.7YTCh. 5 - Prob. 5.8YTCh. 5 - Prob. 5.9YTCh. 5 - Prob. 5.10YTCh. 5 - Prob. 5.11YTCh. 5 - Prob. 5.12YTCh. 5 - Prob. 5.13YTCh. 5 - Prob. 5.14YTCh. 5 - Prob. 5.15YTCh. 5 - Prob. 5.16YTCh. 5 - Prob. 5.17YT
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning