A. Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation).B. Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non-aromatic (neither aromatic nor anti-aromatic).(Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons inthe largest.)1.A.Electrons in a cyclic conjugated system. 18B.The compound is (a, aa, or na) a2.A.Electrons in a cyclic conjugated system. 10B.The compound is (a, aa, or na) na

Step 1:Huckel's Rule states that a compound will display aromaticity if it has the following…

Answered: A. Determine the number of electrons in…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter18: Aromaticity

Section: Chapter Questions

Problem 19CTQ

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A. Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation). B. Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non- aromatic (neither aromatic nor anti-aromatic). (Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons in the largest.) 1. A.Electrons in a cyclic conjugated system. B. The compound is (a, aa, or na) o A.Electrons in a cyclic conjugated system. B.The compound is (a, aa, or na) 2. Previous Next
A. Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation).B. Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non-aromatic (neither aromatic nor anti-aromatic).(Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons in the largest.)
Either the reactant (X) or the major organic product is missing from the equation below. Draw the missing compound. H3C CH3 Pd/C X + H2 CH;CHCHCHCH3 ČH3 • You do not have to consider stereochemistry. • In the case of a missing reactant, there may be more than one answer. If so, draw all possible reactants, • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple reactants using the + sign from the drop-down menu.
1. Label the following rings as aromatic, anti-aromatic, or non-aromatic. Briefly indicate your reasoning for any molecules that are not aromatic. 2. label the hybridization at every non-metallic heteroatom. Н BrMg HN H2N. N. 'N' B. `H. Н N'
| Determine whether the following molecules are aromatic (A), non-aromatic а) (NA), or anti-aromatic (AA). Please provide your answer on the line below each molecule. Additionally, include the total number of conjugated p-orbitals in each molecule (not pi- electrons!) conj. p-orbitals - conj. p-orbitals - conj. p-orbitals conj. p-orbitals
5. Consider each compound below. Note the number of electrons participating in the TT system for each compound and indicate if it is aromatic, anti-aromatic or not aromatic (assume planarity for all molecules). .N. TT electrons TT electrons TT electrons TT electrons Aromatic? Aromatic? Aromatic? Aromatic?
5. Which of the following molecules is aromatic or anti-aromatic? Support your claim with an MO diagram and checking the molecule against the rules of aromaticity. CH
6.
can someone explain why this counts as fully conjugated? does the pos charge count as conjugation? I thought conjugation was sigma bond, pi bond, sigma bond, etc...
Which of the following criteria satisfies non-aromaticity? Choose whichever is applicable. (can be more than one answer) A. Continuous conjugation B. Noncontinuous conjugation C. Pi electrons are equal to 4n+2 D. Pi electrons are equal to 4n E. Planar geometry
Circle any of the following which you think are aromatic systems. For the ones that are aromatic systems, give the "n" (Huckel number.) It's possible tk have more than one. Thank you!
4. Determine if the molecules below are aromatic, antiaromatic, or nonaromatic. If it is not aromatic, explain why.

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