c-) For each pair of resonance structures shown below (A and B), circle which resonance contributor makes a greater contribution to the resonance hybrid. Briefly explain your answer. A B

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c-) For each pair of resonance structures shown below (A and B), circle which resonance

contributor makes a greater contribution to the resonance hybrid. Briefly explain your answer.

O..

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B

m

N:

### Understanding Resonance Structures: Contribution to Resonance Hybrid

#### Problem Statement:
For each pair of resonance structures shown below (A and B), circle which resonance contributor makes a **greater contribution** to the resonance hybrid. Briefly explain your answer.

#### Resonance Structures:
**Structure A:**
- The diagram shows a hexagon representing a benzene ring. 
- One segment of the ring includes an oxygen (O) atom with two lone pairs of electrons depicted, bonded to the nitrogen (N) atom.
- The nitrogen atom also has two lone pairs of electrons.
  
**Structure B:**
- Similar hexagon representing a benzene ring.
- An oxygen (O) atom with three lone pairs of electrons is depicted bonded to the nitrogen (N) atom, which now has a single lone pair of electrons. 

#### Explanation:
The task is to determine which resonance structure (A or B) contributes more significantly to the resonance hybrid and explain why.

Resonance structures are a way to depict delocalized electrons within molecules where the electrons are not associated with a single atom or a single covalent bond. Both structure A and structure B exist in a hybrid form, and the structure with the lower energy (more stability) will make a greater contribution to the resonance hybrid.

**General Rule for Determining Major Resonance Contributor:**
1. The structure with the least number of formal charges
2. The structure with a full octet on more atoms
3. The structure with negative charges on the more electronegative atoms

Based on the given structures:
- **Structure A** has fewer formal charges (none for O, -1 on N).
- **Structure B** has formal charges (O has -1 and N has +1).

Thus, **Structure A** is likely to make a greater contribution to the resonance hybrid because it has fewer formal charges and is more stable.

It is essential for students to draw the resonance structures and calculate formal charges to determine the major contributor.
Transcribed Image Text:### Understanding Resonance Structures: Contribution to Resonance Hybrid #### Problem Statement: For each pair of resonance structures shown below (A and B), circle which resonance contributor makes a **greater contribution** to the resonance hybrid. Briefly explain your answer. #### Resonance Structures: **Structure A:** - The diagram shows a hexagon representing a benzene ring. - One segment of the ring includes an oxygen (O) atom with two lone pairs of electrons depicted, bonded to the nitrogen (N) atom. - The nitrogen atom also has two lone pairs of electrons. **Structure B:** - Similar hexagon representing a benzene ring. - An oxygen (O) atom with three lone pairs of electrons is depicted bonded to the nitrogen (N) atom, which now has a single lone pair of electrons. #### Explanation: The task is to determine which resonance structure (A or B) contributes more significantly to the resonance hybrid and explain why. Resonance structures are a way to depict delocalized electrons within molecules where the electrons are not associated with a single atom or a single covalent bond. Both structure A and structure B exist in a hybrid form, and the structure with the lower energy (more stability) will make a greater contribution to the resonance hybrid. **General Rule for Determining Major Resonance Contributor:** 1. The structure with the least number of formal charges 2. The structure with a full octet on more atoms 3. The structure with negative charges on the more electronegative atoms Based on the given structures: - **Structure A** has fewer formal charges (none for O, -1 on N). - **Structure B** has formal charges (O has -1 and N has +1). Thus, **Structure A** is likely to make a greater contribution to the resonance hybrid because it has fewer formal charges and is more stable. It is essential for students to draw the resonance structures and calculate formal charges to determine the major contributor.
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