Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055 When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.

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Please help me figure out what the slope is and how to calculate the half life Using the data provided. 
 

Time (hr)
In (c/co)
Fraction
Remaining
0
0
1
-0.115
-0.231
2346
-0.345
-0.46
5 -0.576
6
-0.691
7
-0.805
8
-0.921
9 -1.036
10 -1.152
11 -1.266
12 -1.382
18 -2.04
0
0
5
-0.5
≤ -1.5
In (c/c.)
-1
-2
-2.5
In (c/co) vs. Time
10
15
20
Time (hr)
y=-0.114x-0.0055
Transcribed Image Text:Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055
When half of the original amount of starting material has
disappeared, c/c = ½ and the equation In(c/c) = -kt becomes
In(0.5) = -kt… where t, is the half life (the time for half of the
material to decay away). Determine the slope of your In(c/c) vs
t graph and calculate the half life of technetium-99m. Compare
your value to a literature or Internet value for the half life.
Transcribed Image Text:When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.
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