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Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055 When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.

Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055 When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.

Chemistry In Focus
Chemistry In Focus
7th Edition
ISBN:9781337399692
Author:Tro, Nivaldo J.
Publisher:Tro, Nivaldo J.
Chapter9: Energy For Today
Section: Chapter Questions
Problem 9E
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Please help me figure out what the slope is and how to calculate the half life Using the data provided. 
 

Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055
Transcribed Image Text:Time (hr) In (c/co) Fraction Remaining 0 0 1 -0.115 -0.231 2346 -0.345 -0.46 5 -0.576 6 -0.691 7 -0.805 8 -0.921 9 -1.036 10 -1.152 11 -1.266 12 -1.382 18 -2.04 0 0 5 -0.5 ≤ -1.5 In (c/c.) -1 -2 -2.5 In (c/co) vs. Time 10 15 20 Time (hr) y=-0.114x-0.0055
When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.
Transcribed Image Text:When half of the original amount of starting material has disappeared, c/c = ½ and the equation In(c/c) = -kt becomes In(0.5) = -kt… where t, is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life.
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