Use the following to determine the enthalpy of formation of magnesium oxide: Mg (s) + 2HCI (aq) →MgCl2 (aq) + H2 (g) AH=(calculated in the experiment) Mg0 (s) + 2HCI (aq) → MgCl2 (aq)+ H2O (1) AH=(calculated in the experiment) H2 (g) + ½02 (g)→ H20 (1) AH=-285.8 kJ/mol Mg (s) + ½ O2 (g) → Mg0 (s) AH=(determine using Hess's Law) Calculations: 1. Using the enthalpies of reaction computed in the lab and the value given for the enthalpy of formation of liquid water, show the Hess's Law determination of the enthalpy of formation of solid magnesium oxide!
Use the following to determine the enthalpy of formation of magnesium oxide: Mg (s) + 2HCI (aq) →MgCl2 (aq) + H2 (g) AH=(calculated in the experiment) Mg0 (s) + 2HCI (aq) → MgCl2 (aq)+ H2O (1) AH=(calculated in the experiment) H2 (g) + ½02 (g)→ H20 (1) AH=-285.8 kJ/mol Mg (s) + ½ O2 (g) → Mg0 (s) AH=(determine using Hess's Law) Calculations: 1. Using the enthalpies of reaction computed in the lab and the value given for the enthalpy of formation of liquid water, show the Hess's Law determination of the enthalpy of formation of solid magnesium oxide!
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Use the following to determine the enthalpy of formation of magnesium oxide:
Mg (s) + 2HCI (aq) →MgCl2 (aq) + H2 (g)
AH=(calculated in the experiment)
Mg0 (s) + 2HCI (aq) → MgCl2 (aq)+ H2O (1)
AH=(calculated in the experiment)
H2 (g) + ½02 (g)→ H20 (1)
AH=- 285.8 kJ/mol
Mg (s) + ½ O2 (g) → Mg0 (s)
AH=(determine using Hess's Law)
Calculations:
1. Using the enthalpies of reaction computed in the lab and the value given for the enthalpy of formation
of liquid water, show the Hess's Law determination of the enthalpy of formation of solid magnesium
oxide.
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Transcribed Image Text:Room Temperature
Reactant
Mg
Mg
MgO
MgO
Trial Number
3
4
Mass of reactant (from data)
0.2529 g
0.2545 g
0.552g
0.5241 g
Moles of reactant (calculate)
0.01041
0.01047
0.0137
0.0130
Initial time (t) (from graph)
18.0 sec
16.0 sec
30.5 sec
28.5 sec
Initial Temperature (Ti)
(from the graph)
24.2
31.8
30.7
35.2
Linear Curve fit slope (m)
(from the graph)
-0.00655
-0.009704
-0.004660
-0.00858
Linear Curve fit intercept (b)
(from the graph)
37.31
44.71
34.57
39.14
Final Temperature (Tr)
(calculate from linear fit data)
37.31
44.71
34.57
39.14
AT = Tr-T¡
13.11
12.91
3.87
3.94
qwater
13.11
12.91
3.87
3.94
qcalorimeter
131.1 J
129.1 J
38.7 J
39.4 J
qrın
-5616.324 J
-5530.644 J
-1657.908 J
-1687.896 J
598.321 KJ/
mol
528.237 KJ/
mol
120.954 KJ/
mol
129.838 KJ/
AHrxn
mol
Use the following to determine the enthalpy of formation of magnesium oxide:
Mg (s) + 2HCI (aq) → MgCl2 (aq) + H2 (g)
AH=(calculated in the experiment)
Mg0 (s) + 2HCI (aq) → MgCl2 (aq)+ H20 (I)
AH=(calculated in the experiment)
H2 (g) + ½02 (g) → H20 (1)
AH =- 285,8 kJ/mol
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