Trial[I0:][HSO: ]TimeRate[HSO3 ]/time14925316.9Table-2Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide theconcentration of HSO3 with the time in seconds to get the rate.Volume is assumed to be additive in this experiment. Thus, the total volume of all thesolutins is assumed to be 20.0 mL. This introduces a small error that can be consideredinsignicant. The concentrations of IO; and HSO, (after mixing but before the reactionbegins) can be calculated using the relationship: Mailute Vdilute= Mcone Vcone. A samplecalculation is shown below for the concentration of IO, in Trial 1:Mailute to be calculatedVdilue 20.0 mL0.020 M x 2.0 mLMcone 0.020MV conc2.0 mL%3Ddiluted [IO, ] == 0.0020 M IO,%3D20.0 mLSimilarly, the concentration of HSO; in Trial 1 is calculated thus:0.010 M x 2.0 mLdiluted [HSO, ]=0.0010 M HSO,20.0 mL Table-1Exp.Solution ASolution B0.02 Mwater0.01 M HSO3"TotalTimeKIO3Soluition(seconds)12 mL16 mL2 mL20 mL494 mL14 mL2 mL20 mL253.6 mL12 mL2 mL20 mL16.54 @25°C 6 mLmL2 mL20 mL16.54 @45°C 6 mL12 mL2 mL20 mL11.92.

Initial Concentration of KIO3 or IO3- = 0.02 M Initial Concentration of HSO3- = 0.01 M The final…

Answered: Find the concentrations of [IO3] and…

Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the concentration of HSO3 with the time in seconds to get the rate.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Trial
[I0:]
[HSO: ]
Time
Rate
[HSO3 ]/time
1
49
25
3
16.9
Table-2
Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the
concentration of HSO3 with the time in seconds to get the rate.
Volume is assumed to be additive in this experiment. Thus, the total volume of all the
solutins is assumed to be 20.0 mL. This introduces a small error that can be considered
insignicant. The concentrations of IO; and HSO, (after mixing but before the reaction
begins) can be calculated using the relationship: Mailute Vdilute= Mcone Vcone. A sample
calculation is shown below for the concentration of IO, in Trial 1:
Mailute to be calculated
Vdilue 20.0 mL
0.020 M x 2.0 mL
Mcone 0.020M
V conc
2.0 mL
%3D
diluted [IO, ] =
= 0.0020 M IO,
%3D
20.0 mL
Similarly, the concentration of HSO; in Trial 1 is calculated thus:
0.010 M x 2.0 mL
diluted [HSO, ]
=0.0010 M HSO,
20.0 mL

Table-1
Exp.
Solution A
Solution B
0.02 M
water
0.01 M HSO3"
Total
Time
KIO3
Soluition
(seconds)
1
2 mL
16 mL
2 mL
20 mL
49
4 mL
14 mL
2 mL
20 mL
25
3.
6 mL
12 mL
2 mL
20 mL
16.5
4 @25°C 6 mL
mL
2 mL
20 mL
16.5
4 @45°C 6 mL
12 mL
2 mL
20 mL
11.9
2.

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