Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the concentration of HSO3 with the time in seconds to get the rate.
Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the concentration of HSO3 with the time in seconds to get the rate.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Trial
[I0:]
[HSO: ]
Time
Rate
[HSO3 ]/time
1
49
25
3
16.9
Table-2
Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the
concentration of HSO3 with the time in seconds to get the rate.
Volume is assumed to be additive in this experiment. Thus, the total volume of all the
solutins is assumed to be 20.0 mL. This introduces a small error that can be considered
insignicant. The concentrations of IO; and HSO, (after mixing but before the reaction
begins) can be calculated using the relationship: Mailute Vdilute= Mcone Vcone. A sample
calculation is shown below for the concentration of IO, in Trial 1:
Mailute to be calculated
Vdilue 20.0 mL
0.020 M x 2.0 mL
Mcone 0.020M
V conc
2.0 mL
%3D
diluted [IO, ] =
= 0.0020 M IO,
%3D
20.0 mL
Similarly, the concentration of HSO; in Trial 1 is calculated thus:
0.010 M x 2.0 mL
diluted [HSO, ]
=0.0010 M HSO,
20.0 mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff04deb86-1e80-4998-a3e1-f2e8bb7347fb%2F2677b48f-e805-466c-bb42-78541600748a%2Fm1rbci_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Trial
[I0:]
[HSO: ]
Time
Rate
[HSO3 ]/time
1
49
25
3
16.9
Table-2
Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the
concentration of HSO3 with the time in seconds to get the rate.
Volume is assumed to be additive in this experiment. Thus, the total volume of all the
solutins is assumed to be 20.0 mL. This introduces a small error that can be considered
insignicant. The concentrations of IO; and HSO, (after mixing but before the reaction
begins) can be calculated using the relationship: Mailute Vdilute= Mcone Vcone. A sample
calculation is shown below for the concentration of IO, in Trial 1:
Mailute to be calculated
Vdilue 20.0 mL
0.020 M x 2.0 mL
Mcone 0.020M
V conc
2.0 mL
%3D
diluted [IO, ] =
= 0.0020 M IO,
%3D
20.0 mL
Similarly, the concentration of HSO; in Trial 1 is calculated thus:
0.010 M x 2.0 mL
diluted [HSO, ]
=0.0010 M HSO,
20.0 mL
![Table-1
Exp.
Solution A
Solution B
0.02 M
water
0.01 M HSO3"
Total
Time
KIO3
Soluition
(seconds)
1
2 mL
16 mL
2 mL
20 mL
49
4 mL
14 mL
2 mL
20 mL
25
3.
6 mL
12 mL
2 mL
20 mL
16.5
4 @25°C 6 mL
mL
2 mL
20 mL
16.5
4 @45°C 6 mL
12 mL
2 mL
20 mL
11.9
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff04deb86-1e80-4998-a3e1-f2e8bb7347fb%2F2677b48f-e805-466c-bb42-78541600748a%2Fkiidmal_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Table-1
Exp.
Solution A
Solution B
0.02 M
water
0.01 M HSO3"
Total
Time
KIO3
Soluition
(seconds)
1
2 mL
16 mL
2 mL
20 mL
49
4 mL
14 mL
2 mL
20 mL
25
3.
6 mL
12 mL
2 mL
20 mL
16.5
4 @25°C 6 mL
mL
2 mL
20 mL
16.5
4 @45°C 6 mL
12 mL
2 mL
20 mL
11.9
2.
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