Chapter 4.7, Problem 11PPS

To determine

To find: The inverse from the given table.

Answer to Problem 11PPS

The inverse is $\left\{\left(7.4,-3\right),\left(4,-1\right),\left(0.6,1\right),\left(-2.8,3\right),\left(-6.2,5\right)\right\}$ .

Explanation of Solution

Given:

The table is,

$x$	$y$
-3	7.4
-1	4
1	0.6
3	-2.8
5	-6.2

Calculation:

From the given table, the coordinates as ordered pair are:

  $\begin{array}{c}\left(-3,7.4\right)\\ \left(-1,4\right)\\ \left(1,0.6\right)\\ \left(3,-2.8\right)\\ \left(5,-6.2\right)\end{array}$

Exchange the x and y coordinates to obtain the inverse.

$\begin{array}{c}\left(-3,7.4\right)\to \left(7.4,-3\right)\\ \left(-1,4\right)\to \left(4,-1\right)\\ \left(1,0.6\right)\to \left(0.6,1\right)\\ \left(3,-2.8\right)\to \left(-2.8,3\right)\\ \left(5,-6.2\right)\to \left(-6.2,5\right)\end{array}$

Thus, the inverse is $\left\{\left(7.4,-3\right),\left(4,-1\right),\left(0.6,1\right),\left(-2.8,3\right),\left(-6.2,5\right)\right\}$ .