Chapter 4, Problem 7PT

To determine

To write an equation in point-slope form for the line containing EF.

Answer to Problem 7PT

Point slope form of line:

  $y=-\frac{1}{4}x+\frac{27}{4}$

Explanation of Solution

Given information: Given a trapezoid EFGH. Coordinates of E & F:

  $E:(3,6)\&F:(7,5)$

Formula used:

Here we use point slope form of line:

  $y-y_1=m(x-x_1)$

Where, slope m is:

  $m=\frac{y_2-y_1}{x_2-x_1}$

Calculation:

Find the slope using the given two points:

  $m=\frac{5-6}{7-3}=-\frac{1}{4}$

Let’s write the point slope form of line:

  $\begin{array}{l}y-y_1=m(x-x_1)\\ y-6=-\frac{1}{4}(x-3)\\ y=-\frac{1}{4}x+\frac{3}{4}+6\\ y=-\frac{1}{4}x+\frac{27}{4}\end{array}$