Chapter 4.3, Problem 39PPS

To determine

Equation of line that is parallel to $y=7x-3$ and passes through (0, 0)

Answer to Problem 39PPS

The equation of line is $y=7x$ .

Explanation of Solution

Given:

The line is parallel to $y=7x-3$ and passes through origin.

Calculation:

Standard equation of slope intercept form is expressed as follows:

  $y=mx+c$

Here, m is slope and c stands for y -intercept.

Parallel line has same slope. Thus, the slope of parallel line is 7 by comparing with slope-intercept form of the equation.

Substitute the slope in slope-intercept form of the line as follows:

  $y=7x+c$

Substitute the coordinate (0, 0) in above equation as passes through origin as follows:

  $\begin{array}{l}\left(0\right)=7\left(0\right)+c\\ c=0\end{array}$

Thus, the required equation of line is,

  $\begin{array}{l}y=7x+0\\ y=7x\end{array}$