Chapter 4.1, Problem 38PPS

To determine

Whether the point $\left(3,-1\right)$ is on the line $y=\frac{1}{3}x+5$ or not.

Answer to Problem 38PPS

No, the point $\left(3,-1\right)$ is not on the line $y=\frac{1}{3}x+5$ .

Explanation of Solution

Given:

The point is $\left(3,-1\right)$ .

Calculation:

Substitute 3 for x and $-1$ for y in the given equation $y=\frac{1}{3}x+5$ to check whether the point is on the line.

$\begin{array}{l}-1\stackrel{?}{=}\frac{1}{3}\left(3\right)+5\\ -1\stackrel{?}{=}1+5\\ -1\ne 6\end{array}$

Therefore, the point $\left(3,-1\right)$ is not on the line $y=\frac{1}{3}x+5$ .