Chapter 4.7, Problem 10PPS

To determine

To find: The inverse from the given table.

Answer to Problem 10PPS

The inverse is $\left\{\left(-36.4,-8\right),\left(-15.4,-2\right),\left(-4.9,1\right),\left(9.1,5\right),\left(30.1,11\right)\right\}$ .

Explanation of Solution

Given:

The table is,

$x$	$y$
-8	-36.4
-2	-15.4
1	-4.9
5	9.1
11	30.1

Calculation:

From the given table, the coordinates as ordered pair are:

  $\begin{array}{c}\left(-8,-36.4\right)\\ \left(-2,-15.4\right)\\ \left(1,-4.9\right)\\ \left(5,9.1\right)\\ \left(11,30.1\right)\end{array}$

Exchange the x and y coordinates to obtain the inverse.

$\begin{array}{c}\left(-8,-36.4\right)\to \left(-36.4,-8\right)\\ \left(-2,-15.4\right)\to \left(-15.4,-2\right)\\ \left(1,-4.9\right)\to \left(-4.9,1\right)\\ \left(5,9.1\right)\to \left(9.1,5\right)\\ \left(11,30.1\right)\to \left(30.1,11\right)\end{array}$

Thus, the inverse is $\left\{\left(-36.4,-8\right),\left(-15.4,-2\right),\left(-4.9,1\right),\left(9.1,5\right),\left(30.1,11\right)\right\}$ .