Chapter 4.6, Problem 4GP

To determine

To estimate: The attendance for temperature of 90 and 115 degrees, using the data from Guided Practice 3 and a median −fit and compare these values with the answer from the regression line .

Answer to Problem 4GP

Attendance for temperature of 90 degree is 439.18 in median fit line.

Attendance for temperature of 90 degree is 439.415648 in regression line.

Attendance for temperature of 115 degree is 143.68 in median fit line.

Attendance for temperature of 115degree is 143.98114 in regression line

Explanation of Solution

Given information: Swimming: predict the total attendance at a community pool for each of the following temperatures.

  

Calculation:

Let x be the temperature and y be the attendance. ,

Using the above data and graphing calculation the equation of regression line is,

  $y=-11.81738x+\mathrm{1502.97984.}$

So ,equation of median fit line is,

  $y=-11.82x+\mathrm{1502.98.}$

for estimate attendance for temperature of 90 degree substitute x =90 in median fit line.

  $y=-11.82\times 90+1502.98=439.18$ .

for estimate attendance for temperature of 90 degree substitute x =90 in regression line .

  $y=-11.81738\times 90+1502.97984=439.415648$ .

for estimate attendance for temperature of 90 degree substitute x =115 in median fit line.

  $y=-11.82\times 115+1502.98=143.68$ .

for estimate attendance for temperature of 90 degree substitute x =115 in regression line .

  $y=-11.81738\times 115+1502.97984=\mathrm{143.98114.}$