Directing effects of the given compound have to be predicted. The given compound is shown as, Concept Introduction: Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors. Strong deactivators: They are very strong electron withdrawing groups. Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group. Weak deactivators: It consists of halogens. Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing. Strong activators: It contains a lone pair next to the aromatic ring. Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well. Weak activators: It consists of alkyl groups. Halogens are deactivators that are ortho-para directing. Rules to identify the group that dominates the directing effects: Ortho-para directors will always dominate meta directors. Strong activators will always dominate weak activators.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4.6, Problem 4.51P

Interpretation Introduction

Interpretation:

Directing effects of the given compound have to be predicted. The given compound is shown as,

Concept Introduction:

Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.

Strong deactivators: They are very strong electron withdrawing groups.

Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group.

Weak deactivators: It consists of halogens.

Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing.

Strong activators: It contains a lone pair next to the aromatic ring.

Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well.

Weak activators: It consists of alkyl groups.

Halogens are deactivators that are ortho-para directing.

Rules to identify the group that dominates the directing effects:

Ortho-para directors will always dominate meta directors.

Strong activators will always dominate weak activators.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

3. Consider the compounds below and determine if they are aromatic, antiaromatic, or non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly drawn and you should be able to tell that the bonding electrons and lone pair electrons should reside in which hybridized atomic orbital 2. You should consider ring strain- flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti- aromaticity) H H N N: NH2 N Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic TT electrons Me H Me Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic πT electrons H HH…

A chemistry graduate student is studying the rate of this reaction: 2 HI (g) →H2(g) +12(g) She fills a reaction vessel with HI and measures its concentration as the reaction proceeds: time (minutes) [IH] 0 0.800M 1.0 0.301 M 2.0 0.185 M 3.0 0.134M 4.0 0.105 M Use this data to answer the following questions. Write the rate law for this reaction. rate = 0 Calculate the value of the rate constant k. k = Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.

None