
ORGANIC CHEMISTRY-NEXTGEN+BOX (2 SEM.)
4th Edition
ISBN: 9781119761068
Author: Klein
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 4.6, Problem 4.47P
Interpretation Introduction
Interpretation:
Directing effects of the given compound have to be predicted. The given compound is shown as,
Concept Introduction:
Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.
- Strong deactivators: They are very strong electron withdrawing groups.
- Moderate deactivators: It contains a pi bond that is attached to a strong electronegative group.
- Weak deactivators: It consists of halogens.
Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho-para directing.
- Strong activators: It contains a lone pair next to the
aromatic ring. - Moderate activators: It has a lone pair next to the aromatic ring that can take part in the resonance outside the ring as well.
- Weak activators: It consists of alkyl groups.
Halogens are deactivators that are ortho-para directing.
Rules to identify the group that dominates the directing effects:
- Ortho-para directors will always dominate meta directors.
- Strong activators will always dominate weak activators.
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Please help me answer these three questions. Required info should be in data table.
Draw the major organic substitution product or products for (2R,3S)-2-bromo-3-methylpentane reacting with the given
nucleophile. Clearly drawn the stereochemistry, including a wedged bond, a dashed bond and two in-plane bonds at each
stereogenic center. Omit any byproducts.
Bri
CH3CH2O-
(conc.)
Draw the major organic product or products.
Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH.
How many mL of NaOH are needed to reach the first equivalence point?
How many mL of NaOH are needed to reach the second equivalence point?
Chapter 4 Solutions
ORGANIC CHEMISTRY-NEXTGEN+BOX (2 SEM.)
Ch. 4.1 - Consider the following reaction, in which an...Ch. 4.1 - Prob. 4.3PCh. 4.1 - Aromatic rings will also undergo iodination when...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.2 - In each of the following cases, identify the...Ch. 4.3 - Prob. 4.10PCh. 4.3 - Prob. 4.11PCh. 4.3 - Prob. 4.12PCh. 4.3 - Prob. 4.13P
Ch. 4.3 - Prob. 4.14PCh. 4.3 - Predict the products of the following reaction.Ch. 4.3 - Prob. 4.16PCh. 4.3 - Prob. 4.17PCh. 4.4 - Identify the reagents you would use to achieve...Ch. 4.4 - Identify the reagents you would use to achieve...Ch. 4.4 - Identify the reagents you would use to achieve...Ch. 4.4 - Identify the reagents you would use to achieve...Ch. 4.4 - fill in the reagents you would use for the...Ch. 4.4 - fill in the reagents you would use for the...Ch. 4.4 - fill in the reagents you would use for the...Ch. 4.4 - fill in the reagents you would use for the...Ch. 4.4 - Prob. 4.27PCh. 4.4 - Prob. 4.28PCh. 4.4 - And now, for a challenging problem, try to draw...Ch. 4.6 - Prob. 4.31PCh. 4.6 - Prob. 4.32PCh. 4.6 - Prob. 4.33PCh. 4.6 - Prob. 4.34PCh. 4.6 - Prob. 4.35PCh. 4.6 - Prob. 4.36PCh. 4.6 - Prob. 4.37PCh. 4.6 - Prob. 4.40PCh. 4.6 - Prob. 4.41PCh. 4.6 - Predict the products for each of the following...Ch. 4.6 - Predict the products for each of the following...Ch. 4.6 - Predict the products for each of the following...Ch. 4.6 - Predict the products for each of the following...Ch. 4.6 - Prob. 4.47PCh. 4.6 - Prob. 4.48PCh. 4.6 - Prob. 4.49PCh. 4.6 - Prob. 4.50PCh. 4.6 - Prob. 4.51PCh. 4.6 - Prob. 4.52PCh. 4.6 - Prob. 4.53PCh. 4.6 - Prob. 4.54PCh. 4.6 - Prob. 4.55PCh. 4.6 - Prob. 4.56PCh. 4.7 - Prob. 4.58PCh. 4.7 - Prob. 4.59PCh. 4.7 - Prob. 4.60PCh. 4.7 - Prob. 4.61PCh. 4.7 - Prob. 4.62PCh. 4.7 - Prob. 4.63PCh. 4.7 - Prob. 4.64PCh. 4.7 - Prob. 4.65PCh. 4.7 - Prob. 4.66PCh. 4.7 - Prob. 4.67PCh. 4.7 - Can you explain why the following group is a...Ch. 4.7 - Prob. 4.70PCh. 4.7 - Prob. 4.71PCh. 4.7 - Prob. 4.72PCh. 4.7 - Prob. 4.73PCh. 4.7 - Prob. 4.74PCh. 4.7 - Prob. 4.76PCh. 4.7 - Prob. 4.77PCh. 4.7 - Prob. 4.78PCh. 4.7 - Prob. 4.79PCh. 4.8 - Propose an efficient synthesis for each of the...Ch. 4.8 - Propose an efficient synthesis for each of the...Ch. 4.8 - Propose an efficient synthesis for each of the...Ch. 4.8 - Propose an efficient synthesis for each of the...Ch. 4.8 - Propose an efficient synthesis for each of the...Ch. 4.8 - Prob. 4.87PCh. 4.8 - Prob. 4.88PCh. 4.8 - Prob. 4.89PCh. 4.8 - Prob. 4.90PCh. 4.8 - Prob. 4.91PCh. 4.8 - Prob. 4.92PCh. 4.9 - Prob. 4.94PCh. 4.9 - Prob. 4.95PCh. 4.9 - Prob. 4.96PCh. 4.9 - Prob. 4.97PCh. 4.9 - Prob. 4.98PCh. 4.9 - Prob. 4.99PCh. 4.9 - Prob. 4.100PCh. 4.9 - Prob. 4.101PCh. 4.9 - Prob. 4.102P
Knowledge Booster
Similar questions
- Including activity, calculate the solubility of Pb(IO3)2 in a matrix of 0.020 M Mg(NO3)2.arrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M KBr.arrow_forwardIncluding activity, calculate the pH of a 0.010 M HCl solution with an ionic strength of 0.10 M.arrow_forward
- Can I please get the graph 1: Concentration vs. Density?arrow_forwardOrder the following series of compounds from highest to lowest reactivity to electrophilic aromatic substitution, explaining your answer: 2-nitrophenol, p-Toluidine, N-(4-methylphenyl)acetamide, 4-methylbenzonitrile, 4-(trifluoromethyl)benzonitrile.arrow_forwardOrdene la siguiente serie de compuestos de mayor a menor reactividad a la sustitución aromática electrofílica, explicando su respuesta: ácido bencenosulfónico, fluorobenceno, etilbenceno, clorobenceno, terc-butilbenceno, acetofenona.arrow_forward
- Can I please get all final concentrations please!arrow_forwardState the detailed mechanism of the reaction of benzene with isopropanol in sulfuric acid.arrow_forwardDo not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forward
- A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning

Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning