Chapter 4.4, Problem 42PPS

To determine

To complete: the given table

Answer to Problem 42PPS

Area	15	15	15	15	15
Base	1	2	3	4	5
height	30	15	10	7.5	6

Explanation of Solution

Given:

Area is given by $A=\frac{1}{2}bh$

Area	15	15	15	15	15
Base	1	2	3	4	5
height

Calculation:

Area is given by $A=\frac{1}{2}bh$

Height can be calculated as, $h=\frac{2A}{b}$

Now substitute the values of area and base

  $A=15,b=1$

  $h=\frac{15\cdot 2}{1}=30$

Thus, height is 30

  $A=15,b=2$

  $h=\frac{15\cdot 2}{2}=15$

Thus, height is 15

  $A=15,b=3$

  $h=\frac{15\cdot 2}{3}=10$

Thus, height is 10

  $A=15,b=4$

  $h=\frac{15\cdot 2}{4}=7.5$

Thus, height is 7.5

  $A=15,b=5$

  $h=\frac{15\cdot 2}{5}=6$

Thus, height is 6

Area	15	15	15	15	15
Base	1	2	3	4	5
height	30	15	10	7.5	6

Conclusion:

Therefore, the given table is completed.