Chapter 4.1, Problem 12PPS

To determine

To evaluate: $\left(10+9\right)3$ using distributive property

Answer to Problem 12PPS

  $57$

Explanation of Solution

Given information:

  $\left(10+9\right)3$

Concept Used:

Distributive Property: The product sum or difference of two or more numbers inside a parentheses with another number outside the parentheses is equivalent to the sum or difference of product of number outside the parentheses with each number inside the parenthesis. i.e.-

  $a\left(b+c-d\right)=ab+ac-ad$

Calculation:

We can write the given expression in distributive form as-

  $\left(10+9\right)3=\left(10\right)3+\left(9\right)3$

This can further be simplified as-

  $\begin{array}{l}\left(10\right)3+\left(9\right)3=30+27\\ \Rightarrow \left(10\right)3+\left(9\right)3=57\end{array}$