Chapter 4.1, Problem 27PPS

To determine

To evaluate: $-1\left(d-10\right)$ using distributive property

Answer to Problem 27PPS

  $-d+10$

Explanation of Solution

Given information:

  $-1\left(d-10\right)$

Concept Used:

Distributive Property: The product sum or difference of two or more numbers inside a parentheses with another number outside the parentheses is equivalent to the sum or difference of product of number outside the parentheses with each number inside the parenthesis. i.e.-

  $a\left(b+c-d\right)=ab+ac-ad$

Calculation:

  $-1\left(d-10\right)=-1\left(d+\left(-10\right)\right)\mathrm{...}\left[a-b=a+\left(-b\right)\right]$

We can write the given expression in distributive form as-

  $-1\left(d+\left(-10\right)\right)=-1\left(d\right)+\left(-1\right)\left(-10\right)$

This can further be simplified as-

  $-1\left(d\right)+\left(-1\right)\left(-10\right)=-d+10$