Chapter 4.1, Problem 7CYU

To determine

To evaluate: $\left(p+4\right)5$ using distributive property

Answer to Problem 7CYU

  $5p+20$

Explanation of Solution

Given information:

  $\left(p+4\right)5$

Concept Used:

Distributive Property: The product sum or difference of two or more numbers inside a parentheses with another number outside the parentheses is equivalent to the sum or difference of product of number outside the parentheses with each number inside the parenthesis. i.e.-

  $a\left(b+c-d\right)=ab+ac-ad$

Calculation:

We can write the given expression in distributive form as-

  $\left(p+4\right)5=\left(p\right)5+\left(4\right)5$

This can further be simplified as-

  $\left(p\right)5+\left(4\right)5=5p+20$