Chapter 4.1, Problem 51PPS

To determine

To evaluate: $-4\left(j-k\right)$ using distributive property

Answer to Problem 51PPS

  $-4j-4k$

Explanation of Solution

Given information:

  $-4\left(j-k\right)$

Concept Used:

Distributive Property: The product sum or difference of two or more numbers inside a parentheses with another number outside the parentheses is equivalent to the sum or difference of product of number outside the parentheses with each number inside the parenthesis. i.e.-

  $a\left(b+c-d\right)=ab+ac-ad$

Calculation:

  $-4\left(j-k\right)$ can also be written as $-4\left(j+\left(-k\right)\right)$

We can write the given expression in distributive form as-

  $\begin{array}{l}-4\left(j+\left(-k\right)\right)=-4j+\left(-4\right)\left(-k\right)\\ \Rightarrow -4\left(j+\left(-k\right)\right)=-4j-4k\end{array}$