Chapter 4.1, Problem 48PPS

To determine

To evaluate: $3\left(a+b\right)$ using distributive property

Answer to Problem 48PPS

  $3a+3b$

Explanation of Solution

Given information:

  $3\left(a+b\right)$

Concept Used:

Distributive Property: The product sum or difference of two or more numbers inside a parentheses with another number outside the parentheses is equivalent to the sum or difference of product of number outside the parentheses with each number inside the parenthesis. i.e.-

  $a\left(b+c-d\right)=ab+ac-ad$

Calculation:

We can write the given expression in distributive form as-

  $3\left(a+b\right)=3a+3b$