Anatomy & Physiology: The Unity of Form and Function
8th Edition
ISBN: 9781259277726
Author: Kenneth S. Saladin Dr.
Publisher: McGraw-Hill Education
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Chapter 4.4, Problem 18BYGO
Summary Introduction
Introduction:
DNA is a genetic material consisting of a long stretch of
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In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers).
X H X H = female, non-hemophilic
X H X h = female, carrier
X h X h = female, hemophilia
X H Y = male, non-hemophilic
X h Y= male, hemophiliac
a.) Show the cross of a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease?
b.) A woman who is a carrier marries a non-hemophilic man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be?
c.) A woman who has hemophilia marries a non-hemophilic man. How many of their children will have hemophilia, and what is their sex?
A homozygous recessive allele, aa, is responsible for albinism. Humans can exhibit this phenotype. In each
of the following cases, determine the possible genotypes of the mother and father, and of their children:
(a) Both parents have normal phenotypes; some of their children are albino and others are unaffected:
(b) Both parents are albino and have only albino children:
(c) The woman is unaffected, the man is albino, and they have one albino child and three unaffected children:
at a busy hospital. The son of the first couple has hemophilia, a recessive, X-linked
Two mothers give birth to sor
disease. Neither parent from couple #1 has the disease. The second couple has an unaffected son, despite the fact
that the father has hemophilia. The two couples challenge the hospital in court, claiming their babies must have beer
swapped at birth. You must advise as to whether or not the sons could have been swapped. What would you say?
5. In a dispute over parentage, the mother of a child with…
Cystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1 in 1,700. Assume Hardy-Weinberg proportions.
What is the probability that the wife is also a carrier? Answer in decimal number only (three decimal places; example: 0.123).
What is the probability that their first child will be affected? Answer in decimal number only (three decimal places; example: 0.123).
Chapter 4 Solutions
Anatomy & Physiology: The Unity of Form and Function
Ch. 4.1 - What are the three components of a nucleotide?...Ch. 4.1 - What governs the pattern of base paring in DNA?Ch. 4.1 - what is the difference between DNA and chromatin?Ch. 4.1 - Summarize the structural and functional...Ch. 4.1 - The general name of the monomers that compose DNA...Ch. 4.1 - Prob. 2AYLOCh. 4.1 - Prob. 3AYLOCh. 4.1 - How DNA and protein are combined to form...Ch. 4.1 - Prob. 5AYLOCh. 4.1 - HOW RNA differs from DNA in structure and...
Ch. 4.2 - Prob. 5BYGOCh. 4.2 - Describe the roles of RNA polymerase ribosomes,...Ch. 4.2 - What is the difference between genetic...Ch. 4.2 - Summarize the processing of a protein from the...Ch. 4.2 - Prob. 9BYGOCh. 4.2 - Prob. 10BYGOCh. 4.2 - Prob. 1AYLOCh. 4.2 - Prob. 2AYLOCh. 4.2 - The organization of nucleotides into DNA triplets;...Ch. 4.2 - How the genetic code relates mRNA codons to...Ch. 4.2 - The process and outcome of genetic transcription,...Ch. 4.2 - Prob. 6AYLOCh. 4.2 - Prob. 7AYLOCh. 4.2 - Prob. 8AYLOCh. 4.2 - Prob. 9AYLOCh. 4.2 - Prob. 10AYLOCh. 4.3 - Describe the genetic roles of DNA helicase and DNA...Ch. 4.3 - Explain why DNA replication is called...Ch. 4.3 - Define mutation. Explain why some mutations are...Ch. 4.3 - Prob. 14BYGOCh. 4.3 - Prob. 15BYGOCh. 4.3 - Prob. 16BYGOCh. 4.3 - Prob. 1AYLOCh. 4.3 - Semiconservative replication, the enzymes that...Ch. 4.3 - What a mutation is and how a cell detects and...Ch. 4.3 - The four stages of the cell cycle, what occurs in...Ch. 4.3 - Prob. 5AYLOCh. 4.3 - Cytokinesis and how it overlaps but differs from...Ch. 4.3 - Prob. 7AYLOCh. 4.3 - Prob. 8AYLOCh. 4.4 - Why must the carrier of a genetic disease be...Ch. 4.4 - Prob. 18BYGOCh. 4.4 - Prob. 19BYGOCh. 4.4 - Prob. 1AYLOCh. 4.4 - Organization of the karyotype; the number of...Ch. 4.4 - Prob. 3AYLOCh. 4.4 - Prob. 4AYLOCh. 4.4 - Prob. 5AYLOCh. 4.4 - Why a recessive trait can skip a generation, with...Ch. 4.4 - The differences between the genotype, genome, and...Ch. 4.4 - Prob. 8AYLOCh. 4.4 - Prob. 9AYLOCh. 4.4 - Prob. 10AYLOCh. 4.4 - Prob. 11AYLOCh. 4.4 - Prob. 12AYLOCh. 4.4 - Why it cannot be said that dominant alleles are...Ch. 4.4 - Prob. 14AYLOCh. 4 - Production of more than one phenotypic trait by a...Ch. 4 - When a ribosome reads a codon on mRNA, it must...Ch. 4 - Prob. 3TYRCh. 4 - Two genetically identical strands of a metaphase...Ch. 4 - Prob. 5TYRCh. 4 - Genetic transcription is performed by a....Ch. 4 - Prob. 7TYRCh. 4 - Prob. 8TYRCh. 4 - Semiconservative replication occurs during a....Ch. 4 - Mutagens sometimes cause no harm to cells for all...Ch. 4 - The cytoplasmic division at the end of mitosis is...Ch. 4 - Prob. 12TYRCh. 4 - Prob. 13TYRCh. 4 - Prob. 14TYRCh. 4 - Prob. 15TYRCh. 4 - Prob. 16TYRCh. 4 - Prob. 17TYRCh. 4 - The cytoplasmic granule of RNA and protein that...Ch. 4 - Prob. 19TYRCh. 4 - Prob. 20TYRCh. 4 - Prob. 1BYMVCh. 4 - Prob. 2BYMVCh. 4 - Prob. 3BYMVCh. 4 - Prob. 4BYMVCh. 4 - Prob. 5BYMVCh. 4 - Prob. 6BYMVCh. 4 - Prob. 7BYMVCh. 4 - Prob. 8BYMVCh. 4 - Prob. 9BYMVCh. 4 - Prob. 10BYMVCh. 4 - Prob. 1WWTSCh. 4 - Steroids, carbohydrates, and phospholipids are...Ch. 4 - Prob. 3WWTSCh. 4 - Prob. 4WWTSCh. 4 - Prob. 5WWTSCh. 4 - The law of complementary base pairing describes...Ch. 4 - Prob. 7WWTSCh. 4 - All mutations result m the production of defective...Ch. 4 - Prob. 9WWTSCh. 4 - Prob. 10WWTSCh. 4 - Why world the supercoiled, condensed form of...Ch. 4 - Prob. 2TYCCh. 4 - Given the information in this chapter, present an...Ch. 4 - Prob. 4TYCCh. 4 - Prob. 5TYC
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- Classical hemophilia is a sex-linked disease caused by a recessive gene on the X chromosome. (Hemophilia refers to diseases that cause delays in blood clotting.) If a woman who is acarrierof classical hemophilia has children with a normal male, give the ratios of the possible offspring with respect to classical hemophilia. Be sure to state both the genotypes and the phenotypes of each offspring. For genotypes, use X for a normal X chromosome, Xh for an X chromosome with the hemophilia gene, and Y for a normal Y chromosome. For phenotypes, if the offspring is female, be sure to state if homozygous normal, a carrier, or has the disease. If the offspring is a male, be sure to state if normal or has the disease.arrow_forwardIn genetics, what does a genotype of Hh signify? Choose 1 answer: Choose 1 answer: (Choice A) A Homozygous; two dominant alleles (Choice B) B Homozygous; two recessive alleles (Choice C) C Heterozygous; one dominant allele and one recessive allele (Choice D) D Homozygous; one dominant allele and one recessive allelearrow_forwardFor an individual expressing the dominant phenotype, explain why you must list two possible genotypes.arrow_forward
- The father of five children begins to show symptoms of huntington disease. what is the probability that same, the man's second oldest son (11-2),, will suffer from the disease if he lives a normal life span? Sam's mother and her ancestors do not have the diseas. Sam's father was adopted, so we do not know his biological family history for hunutington disease. Explore all possible outcome for sam and explain your reasoningarrow_forwardA couple are both phenotypically normal but their son suffers from hemophilla, a sex linked recessive disorder. What fraction of their children are likely to suffer from hemophilia. what fraction are likely to be carriers.arrow_forwardWhat are two possible explanations for why the same genotype (DNA) can result in different phenotypes (result)arrow_forward
- Hemophilia is a blood disorder which is sex-linked. A woman carrier has children with a normal man. Determine the chances for girls and boys with hemophilia. [Remember that females have the XX genotype and males have the XY genotype. Do not place an allele on the Y chromosome. Example: XN Xn for female; Xn Y for male]arrow_forwardThe allele for albinism is recessive to the allele for normal skin pigmentation. All individuals who are homozygous for this recessive allele (m) are unable to produce the enzyme needed for melanin production and are referred to as albinos. In the following statements, determine the correct genotypes: An albino male (genotype A) whose parents both have normal skin pigmentation (genotype B) marries a woman who does not have albinism (genotype C). This woman’s father is an albino (genotype D). The married couple has three children, two with normal skin pigmentation (genotype E) and one exhibiting albinism (genotype F)arrow_forwardQUESTION 5 For the following pedigree, assume that the mode of inheritance is X-linked dominant, and that the trait has full penetrance and expressivity. I 11 IV 1 2 3 4 1 2 5 6 7 8 HOOD OD FO 1 2 3 4 5 6 7 8 9 1 2 3 4 OOD OC 10 11 12 13 14 15 ☐☐ 5678arrow_forward
- Examine the human karyotype shown below. In the space provided, A) identify the sex of the individual B) state the name of the disorder this individual has C) state how you know based on their karyotype. 10 11 12 13 14 15 16 17 18 19 20 21 22arrow_forwardThe following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Fill in the punnett square and answer the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?arrow_forwardGiven that the individual has a dominant phenotype, is it possible to determine its genotype?arrow_forward
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