University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)
14th Edition
ISBN: 9780321982582
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Textbook Question
Chapter 41, Problem 41.8DQ
In the ground state of the helium atom one electron must have “spin down” and the other “spin up.” Why?
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B) A spin state in an arbitrary direction is given by
directions.
Cas
2
-io
sin
2
Find the form of the states in z, x and y
(II) For each of the following atomic transitions, state
whether the transition is allowed or forbidden, and why:
(a) 4p → 3p; (b) 3p → 1s; (c) 4d → 2d; (d) 5d → 3s;
(e) 4s → 2p.
(4) Electronic energy level of a hydrogen atom is given by
R
; п %3D 1,2, 3,...
n2
E = -
and R = 13.6 eV. Each energy level has degeneracy 2n2 (degeneracy is the number of equivalent
configurations associated with the energy level).
(a) Derive the partition function for a hydrogen atom at a constant temperature.
(b) Consider that the energy level of a hydrogen atom is approximated by a two level system,
n = 1,2. Estimate the mean energy at 300 K.
Chapter 41 Solutions
University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)
Ch. 41.1 - Prob. 41.1TYUCh. 41.2 - Prob. 41.2TYUCh. 41.3 - Prob. 41.3TYUCh. 41.4 - In this section we assumed that the magnetic field...Ch. 41.5 - In which of the following situations is the...Ch. 41.6 - Prob. 41.6TYUCh. 41.7 - Prob. 41.7TYUCh. 41.8 - Prob. 41.8TYUCh. 41 - Prob. 41.1DQCh. 41 - Prob. 41.2DQ
Ch. 41 - Prob. 41.3DQCh. 41 - Prob. 41.4DQCh. 41 - Prob. 41.5DQCh. 41 - Prob. 41.6DQCh. 41 - Prob. 41.7DQCh. 41 - In the ground state of the helium atom one...Ch. 41 - Prob. 41.9DQCh. 41 - Prob. 41.10DQCh. 41 - Prob. 41.11DQCh. 41 - Prob. 41.12DQCh. 41 - Prob. 41.13DQCh. 41 - Prob. 41.14DQCh. 41 - Prob. 41.15DQCh. 41 - Prob. 41.16DQCh. 41 - Prob. 41.17DQCh. 41 - Prob. 41.18DQCh. 41 - Prob. 41.19DQCh. 41 - Prob. 41.20DQCh. 41 - Prob. 41.21DQCh. 41 - Prob. 41.22DQCh. 41 - Prob. 41.23DQCh. 41 - Prob. 41.1ECh. 41 - Prob. 41.2ECh. 41 - Prob. 41.3ECh. 41 - Prob. 41.4ECh. 41 - Prob. 41.5ECh. 41 - Prob. 41.6ECh. 41 - Prob. 41.7ECh. 41 - Prob. 41.8ECh. 41 - Prob. 41.9ECh. 41 - Prob. 41.10ECh. 41 - Prob. 41.11ECh. 41 - Prob. 41.12ECh. 41 - Prob. 41.13ECh. 41 - Prob. 41.14ECh. 41 - Prob. 41.15ECh. 41 - Prob. 41.16ECh. 41 - Prob. 41.17ECh. 41 - Prob. 41.18ECh. 41 - A hydrogen atom in a 3p state is placed in a...Ch. 41 - Prob. 41.20ECh. 41 - Prob. 41.21ECh. 41 - Prob. 41.22ECh. 41 - Prob. 41.23ECh. 41 - Prob. 41.24ECh. 41 - Prob. 41.25ECh. 41 - Prob. 41.26ECh. 41 - Prob. 41.27ECh. 41 - Prob. 41.28ECh. 41 - Prob. 41.29ECh. 41 - (a) Write out the ground-state electron...Ch. 41 - Prob. 41.31ECh. 41 - Prob. 41.32ECh. 41 - Prob. 41.33ECh. 41 - Prob. 41.34ECh. 41 - Prob. 41.35ECh. 41 - Prob. 41.36ECh. 41 - Prob. 41.37ECh. 41 - Prob. 41.38ECh. 41 - Prob. 41.39PCh. 41 - Prob. 41.40PCh. 41 - Prob. 41.41PCh. 41 - Prob. 41.42PCh. 41 - Prob. 41.43PCh. 41 - Prob. 41.44PCh. 41 - Prob. 41.45PCh. 41 - Prob. 41.46PCh. 41 - Prob. 41.47PCh. 41 - Prob. 41.48PCh. 41 - Prob. 41.49PCh. 41 - Prob. 41.50PCh. 41 - Prob. 41.51PCh. 41 - Prob. 41.52PCh. 41 - Prob. 41.53PCh. 41 - Prob. 41.54PCh. 41 - Prob. 41.55PCh. 41 - Prob. 41.56PCh. 41 - Prob. 41.57PCh. 41 - Effective Magnetic Field. An electron in a...Ch. 41 - Prob. 41.59PCh. 41 - Prob. 41.60PCh. 41 - Prob. 41.61PCh. 41 - Prob. 41.62PCh. 41 - Prob. 41.63PCh. 41 - Prob. 41.64PCh. 41 - Prob. 41.65PCh. 41 - Prob. 41.66PCh. 41 - Prob. 41.67PCh. 41 - Prob. 41.68CPCh. 41 - Prob. 41.69CPCh. 41 - Prob. 41.70PPCh. 41 - Prob. 41.71PPCh. 41 - Prob. 41.72PPCh. 41 - Prob. 41.73PP
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- (3) Calculate (x²) for in the quantum state {n = 2, l = 1, m = average can be expressed more simply as (2,1,1|x2|2,1,1) where the ket |n, l, m) defines the quantum state 1} for a hydrogen atom. Notice that this of a hydrogen atom, but, as done in class, the spin quantum number is not included.arrow_forwardTrue or false ? Non determinism only applies in the direction of the transition, just because an 'a' forces you to be in two states does not mean you cannot be in just one of the two alone via some other path.arrow_forwardSuppose that the electron had no spin and that the Pauli exclusion principle still held.Which, if any, of the present noble gases would remain in that category?arrow_forward
- if the chlorine molecule at 290K were to rotate at the angular frequency predicted by the equipartition theorem what would be the average centipital force ? ( the atoms of Cl are 2 x 10-10 m apart and the mass of the chlorine atom 35.45 a.m.u )arrow_forward(4) Electronic energy level of a hydrogen atom is given by R E ; n = n2 1, 2, 3,... and R = 13.6 eV. Each energy level has degeneracy 2n² (degeneracy is the number of equivalent configurations associated with the energy level). (a) Calculate the partition function Z for a hydrogen atom at a constant temperature. (b) Let us consider that the energy level of a hydrogen atom is approximated by a two level system, n = 1,2. Estimate the mean energy at 300 K.arrow_forwardPlease asaparrow_forward
- (i) Using Bohr model for atomic hydrogen, obtain energy levels for the 2s, 3s and 3p states in the actual number with the unit of [eV]. We consider a transition that electron in the 3p state emits a photon and make a transition to the 2s state. What is the frequency v of this photon ? (ii) Now we do not include electron spin angular momentum, and just estimate an effect of a magnetic field B on this transition (Normal Zeeman effect) with orbital angular momentum. How many lines of optical transition do we expect ? What is the interval of the frequency in the field B = 0.1 Tesla ? (iii) In this situation, we do not expect transition from 3s to 2s state if the electron is initially in the 3s state, Explain the reason. (iv) We now consider an effect of magnetic field B to a free electron spin (not in Hydrogen, but a free electron). The magnetic field of B = 1.0 Tesla will split the energy level into two (Zeeman) levels. Obtain the level difference in the unit of [eV] from the value of…arrow_forwardWhat if electrons were spin-3/2 instead of spin-1/2. What would be Z for the first noble gas in this situation, and how do you know?arrow_forwardThe magnitudes of the resultant spins of the electrons of the elements B through Ne when in the ground state are: 3h/2 , 2h, 15h/2, 2h , 3h/2 , and 0, respectively. Argue that these spins are consistent with Hund's rule.arrow_forward
- For a one-electron atom or ion, spinorbit coupling splits all states except s states into doublets. Why are s states exceptions to this rule?arrow_forwardAn election in a hydrogen atom is in 3p state. Find the smallest angle the magnetic moment makes with the z-axis. (Express your answer in terms of µB.)arrow_forwardWhat is the maximum number of orbital angular momentum electron states in the n = 2 shell of a hydrogen atom? (Ignore election spin.)arrow_forward
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