The narrow gap between two closely spaced circular plates initially is filled with incompressible liquid. At t = 0 the upper plate, initially h 0 above the lower plate, begins to move downward toward the lower plate with constant speed, V 0 , causing the liquid to be squeezed from the narrow gap. Neglecting viscous effects and assuming uniform flow in the radial direction, develop an expression for the velocity field between the parallel plates. Hint : Apply conservation of mass to a control volume with the outer surface located at radius r . Note that even though the speed of the upper plate is constant, the flow is unsteady. For V 0 = 0 . 01 m/s and h 0 = 2 mm, find the velocity at the exit radius R = 100 mm at t = 0 and t = 0 . 1 s. Plot the exit velocity as a function of time, and explain the trend.
The narrow gap between two closely spaced circular plates initially is filled with incompressible liquid. At t = 0 the upper plate, initially h 0 above the lower plate, begins to move downward toward the lower plate with constant speed, V 0 , causing the liquid to be squeezed from the narrow gap. Neglecting viscous effects and assuming uniform flow in the radial direction, develop an expression for the velocity field between the parallel plates. Hint : Apply conservation of mass to a control volume with the outer surface located at radius r . Note that even though the speed of the upper plate is constant, the flow is unsteady. For V 0 = 0 . 01 m/s and h 0 = 2 mm, find the velocity at the exit radius R = 100 mm at t = 0 and t = 0 . 1 s. Plot the exit velocity as a function of time, and explain the trend.
The narrow gap between two closely spaced circular plates initially is filled with incompressible liquid. At t = 0 the upper plate, initially h0 above the lower plate, begins to move downward toward the lower plate with constant speed, V0, causing the liquid to be squeezed from the narrow gap. Neglecting viscous effects and assuming uniform flow in the radial direction, develop an expression for the velocity field between the parallel plates. Hint: Apply conservation of mass to a control volume with the outer surface located at radius r. Note that even though the speed of the upper plate is constant, the flow is unsteady. For V0 = 0.01 m/s and h0 = 2 mm, find the velocity at the exit radius R = 100 mm at t = 0 and t = 0.1 s. Plot the exit velocity as a function of time, and explain the trend.
A piston moves with constant velocity U0 in a cylinder having radius R. A liquid having density leaves the open end with conical velocity proÖle V~ = V0(1-r/R)^k.Figure for problem 1.(a) If the exhaust port is closed, find the value of V0 in terms of U0. Be sure to define an appropriate control volume for solving this problem.(b) If V0 = U0, find the volume áow rate leaving through the exhaust port (in terms of U0 and R)
An airplane is flying at 350 mi/h at 4000 m standard altitude. As is typical, the air velocity relative to the upper
surface of the wing, near its maximum thickness, is 26 percent higher than the plane's velocity. Using
Bernoulli's equation, calculate the absolute pressure at this point on the wing. Neglect elevation changes and
compressibility. (The properties of air at 4000 m are p = 61633 Pa, p = 0.8191 kg/m³)
Pa
Air flows steadily at a pressure of 105 kPa at a speed of 0.1m / s and a temperature of 300K in a duct with a diameter of 10 cm.
After a deformation in the duct, the flow is uniformly out of the gap with dimensions of 3cm × 6cm out of the possible state. Act like a complete gas, you can make R = 287J / kg.k Assuming an incompressible flow, calculate the velocity of air out of the gap.
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8.01x - Lect 27 - Fluid Mechanics, Hydrostatics, Pascal's Principle, Atmosph. Pressure; Author: Lectures by Walter Lewin. They will make you ♥ Physics.;https://www.youtube.com/watch?v=O_HQklhIlwQ;License: Standard YouTube License, CC-BY