Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.31P
(a)
To determine
The specific power of
(b)
To determine
The specific power of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The intensity of radiation at 10 ft was 200 R/hr. If the technologist moved to 5 ft from the source of radiation, what would the exposure be?
O a. 400 R/hr
Ob. 800 R/hr
Oc. 100 R/hr
Od, 50 R/hr
250 mA and .2 sec creates a good radiograph of a lateral thoracic spine withappropriate exposure to the IR. The technologist wants to modify this technique to give the patient time to breathe during the exposure. If the time is changed to 2 seconds, what new mA will maintain exposure?
25. A radiograph made with an exposure of 12 mA per minute has a density of 0.8 in the area of
interest. It is desired to increase the density to 2.0 in this area. By reference to a characteristic curve of
the film, it is found that the difference in log e between a density of 0.8 and 2.0 is 0.76. The
antilogarithm of log 0.76 is 5.8 (relative exposure factor). What must the new exposure time be to
produce a radiograph with a density of 2.0, assuming the first exposure time was 1 minute?
Chapter 4 Solutions
Introduction To Health Physics
Ch. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - If we start with 5 mg of 210Pb , what would be the...Ch. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - For use in carcinogenesis studies, benzo(a)pyrene...
Ch. 4 - Prob. 4.11PCh. 4 - Calculate the number of beta particles emitted per...Ch. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - How much 234U is there in 1 metric ton of the...Ch. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - The mean concentration of potassium in crustal...Ch. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - What is the (a) half-life? (b) mean life (in...Ch. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- 1. Consider the following data from the analysis of mercury using cold vapor atomic absorption spectrometry: Concentration (ppm) 10.0 1.00 0.000 No. of replicate 15 15 20 measurements Mean of S 9.95 1.15 0.0124 Standard deviation of 0.12 0.030 0.0075 the measurement, s The calibration data yielded the following equation: S= 1.09CHE + 0.298 Where CHg is the concentration in ppm of Hg and S is the relative intensity of the emission line of Hg. Calculate for the following: a. Calibration sensitivity b. Analytical sensitivity at 10.0 and 1.00 ppm of Hg; and С. Detection limitarrow_forwardA radioactive source is producing 1.50 MeV gamma rays. If two detectors are placed 4.00 m and 7.00 m away respectively, what is the ratio of the measured intensities of the near detector over the far detector (I2/I1)? Do NOT include units in your answer answer to 2 decimal places.arrow_forwardDensity is the ratio of mass to volume. If a uranium nucleus has a radius of 7.4 femtometers and nuclear mass of 238 AMU, what is its density in kg/m3? Assume the nucleus is sphere-shaped to find its volume.arrow_forward
- A radiographic technique calls for 46 kVp and 28 mAs which results in an exposure of 278 µGy. What is the expected exposure if the technique is changed to 75 kVp and 14 mAs? Round your answer to the nearest whole number. Do not include units.arrow_forwardif a record sample has rate of 44100Hz, how many samples are required to capture 0.25s?arrow_forwardIf power is set to .80, this implies: a) that the Type I error is set to .20 b) that the Type II error is set to .20 c) that the alpha level is set to .08 d) that the beta is .80 as wellarrow_forward
- Problem 1 Use the properties of Gamma functions to solve these expressions by hand. a program such as a T[ ] × [4] b C 3 — 92 xr 5 9 T[-2] × [2] Г xr 4 4arrow_forwardFull explan..arrow_forwardThe recommended adult dose of Elixophillin, a drug used to treat asthma, is 6mg/kg of body mass. Calculate the dose in milligrams for a 150lb person.arrow_forward
- An exposure using 10 mAs and 70 kVp results in a DI of +2.8. If you were going to fix this overexposure by changing mAs, what would your new mAs need to be? New mAs _________________ If you were going to leave mAs the same and fix this overexposure by changing kV, what would your new kV need to be? New kV __________________arrow_forwardA patient is exposed to 210 rad of gamma rays. What is the dose the patient receives in rem? Express your answer using two significant figures. Dose = Η ΜΕ ΑΣΦ Submit Request Answer 0 ? remarrow_forward2. 134I1- Protons____ Neutrons____ Electronsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University