A pharmaceutical product, P, is made in a batch reactor. The reactor effluent goes through a purifiation process to yield a final product stream and a waste stream. The initial charge (feed) to the reactor and the final product are each weighed, and the reactor effluent, final product, and waste stream are each analyzed for P. The analyzer calibration is a series of meter readings, R. corresponding to known mass fractions of P, ,vP.
Xp | 0.08 | 0.16 | 0.25 | 0.45 |
R | 105 | 160 | 245 | 360 |
- Plot the analyzer calibration data on logarithmic axes and determine an expression for xp(R).
Batch #: 23601 Date: 10/4 Mass charged to reactor: 2253 kg Mass of purified product: 1239 kg Reactor effluent analysis: R = 388 Final product analysis: R = 583 Waste stream analysis: R = 140
Calculate the mass fractions of P in all three streams. Then calculate the percentage yield of the purification process,
kg P in final product . „„„
YP=
™
X 100%
kg P in reactor effluent
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
ELEM.PRIN.OF CHEMICAL PROC.-W/ACCESS
Additional Engineering Textbook Solutions
Elementary Surveying: An Introduction To Geomatics (15th Edition)
Database Concepts (8th Edition)
Introduction To Programming Using Visual Basic (11th Edition)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Problem Solving with C++ (10th Edition)
Starting Out with Java: From Control Structures through Objects (7th Edition) (What's New in Computer Science)
- please, provide me with right resultsarrow_forwardEx. HW. A vertical glass tube, 2cm ID & 5m long in heated uniformly over its length. The water enter at (200-204 C) & 68.9 bar calculated the pressure drop if the flowrate 0.15 Kg/s & the power applied as a heat to the fluid is 100KW using the homogeneous model. Given that enthalpy at inlet temp.=0.87MJ/Kg, enthalpy saturation temp (285C)=1.26 MJ/Kg and μl=0.972*10-4 Ns/m2, μG=2.89*10-5 Ns/m2, UG=2.515*10-2m3/Kg and the change in UG over range of pressure=-4.45*10-4m3/Kg/bar.arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward
- and the viscosity of the water is 1.24 × 104 Nsm 2. Answer: Slug flow 1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³.arrow_forwardA chemical reaction takes place in a container of cross-sectional area 50.0 cm2. As a result of the reaction, a piston is pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done (in J) by the system.arrow_forwardExample 7.2 Steam is generated in a high pressure boiler containing tubes 2.5 m long and 12.5 mm internal diameter. The wall roughness is 0.005 mm. Water enters the tubes at a pressure of 55.05 bar and a temperature of 270°C, and the water flow rate through each tube is 500 kg/h. Each tube is heated uniformly at a rate of 50 kW. Calle (a) Estimate the pressure drop across each tube (neglecting end effects) using (i) the homogeneous flow model and (ii) the Martinelli-Nelson correlation. (b) How should the calculation be modified if the inlet temperature were 230°C at the same pressure?arrow_forward
- Please solve this question by simulation in aspen hysysarrow_forward(11.35. For a binary gas mixture described by Eqs. (3.37) and (11.58), prove that: 4812 Pу132 ✓ GE = 812 Py1 y2. ✓ SE dT HE-12 T L = = (812 - 7 1/8/123) d² 812 Pylyz C=-T Pylyz dT dT² See also Eq. (11.84), and note that 812 = 2B12 B11 - B22. perimental values of HE for binary liquid mixtures ofarrow_forwardplease provide me the solution with more details. because the previous solution is not cleararrow_forward
- Introduction to Chemical Engineering Thermodynami...Chemical EngineeringISBN:9781259696527Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark SwihartPublisher:McGraw-Hill EducationElementary Principles of Chemical Processes, Bind...Chemical EngineeringISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEYElements of Chemical Reaction Engineering (5th Ed...Chemical EngineeringISBN:9780133887518Author:H. Scott FoglerPublisher:Prentice Hall
- Industrial Plastics: Theory and ApplicationsChemical EngineeringISBN:9781285061238Author:Lokensgard, ErikPublisher:Delmar Cengage LearningUnit Operations of Chemical EngineeringChemical EngineeringISBN:9780072848236Author:Warren McCabe, Julian C. Smith, Peter HarriottPublisher:McGraw-Hill Companies, The