(a)
Interpretation:
Lithium nitrate is soluble in water or not is to be determined.
Concept introduction:
A solution is a combination of two parts: solute and solvent. A solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution.
A compound is soluble in water when the forces between the ions or atoms of the compound and ions of water molecules are greater than forces between the ions or atoms themselves in a compound. Ionic and polar covalent compounds are soluble in water.
In an ionic compound, the ions get separates in the water and form cations and anions. The positive end of water is attracted towards the anions and the negative end of water is attracted towards the cations. The ions get hydrated and the compound dissolves.
In polar covalent compounds, the atoms get polarized in the water molecule and become partially positive charged and partially negative charged. The positive end of water is attracted towards the partially negative charged atom and the negative end of water is attracted towards the partially positive charged. The atoms get hydrated and the compound dissolves.
In nonpolar covalent compounds, there is no electronegativity difference between the atoms so there will be no polarization of the compound. Therefore, these compounds will interact less with water and are insoluble in water.
(b)
Interpretation:
Glycine
Concept introduction:
A solution is a combination of two parts: solute and solvent. A solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution.
A compound is soluble in water when the forces between the ions or atoms of the compound and ions of water molecules are greater than forces between the ions or atoms themselves in a compound. Ionic and polar covalent compounds are soluble in water.
In an ionic compound, the ions get separates in the water and form cations and anions. The positive end of water is attracted towards the anions and the negative end of water is attracted towards the cations. The ions get hydrated and the compound dissolves.
In polar covalent compounds, the atoms get polarized in the water molecule and become partially positive charged and partially negative charged. The positive end of water is attracted towards the partially negative charged atom and the negative end of water is attracted towards the partially positive charged. The atoms get hydrated and the compound dissolves.
In non-polar covalent compounds, there is no electronegativity difference between the atoms so there will be no polarization of the compound. Therefore, these compounds will interact less with water and are insoluble in water.
(c)
Interpretation:
Pentane is soluble in water or not is to be determined.
Concept introduction:
A solution is a combination of two parts: solute and solvent. A solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution.
A compound is soluble in water when the forces between the ions or atoms of the compound and ions of water molecules are greater than forces between the ions or atoms themselves in a compound. Ionic and polar covalent compounds are soluble in water.
In an ionic compound, the ions get separates in the water and form cations and anions. The positive end of water is attracted towards the anions and the negative end of water is attracted towards the cations. The ions get hydrated and the compound dissolves.
In polar covalent compounds, the atoms get polarized in the water molecule and become partially positive charged and partially negative charged. The positive end of water is attracted towards the partially negative charged atom and the negative end of water is attracted towards the partially positive charged. The atoms get hydrated and the compound dissolves.
In non-polar covalent compounds, there is no electronegativity difference between the atoms so there will be no polarization of the compound. Therefore, these compounds will interact less with water and are insoluble in water.
(d)
Interpretation:
Ethylene glycol
Concept introduction:
A solution is a combination of two parts: solute and solvent. A solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution.
A compound is soluble in water when the forces between the ions or atoms of the compound and ions of water molecules are greater than forces between the ions or atoms themselves in a compound. Ionic and polar covalent compounds are soluble in water.
In an ionic compound, the ions get separates in the water and form cations and anions. The positive end of water is attracted towards the anions and the negative end of water is attracted towards the cations. The ions get hydrated and the compound dissolves.
In polar covalent compounds, the atoms get polarized in the water molecule and become partially positive charged and partially negative charged. The positive end of water is attracted towards the partially negative charged atom and the negative end of water is attracted towards the partially positive charged. The atoms get hydrated and the compound dissolves.
In non-polar covalent compounds, there is no electronegativity difference between the atoms so there will be no polarization of the compound. Therefore, these compounds will interact less with water and are insoluble in water.
Want to see the full answer?
Check out a sample textbook solution
Chapter 4 Solutions
Chemistry: The Molecular Nature of Matter and Change
- + C8H16O2 (Fatty acid) + 11 02 → 8 CO2 a. Which of the above are the reactants? b. Which of the above are the products? H2o CO₂ c. Which reactant is the electron donor? Futty acid d. Which reactant is the electron acceptor? e. Which of the product is now reduced? f. Which of the products is now oxidized? 02 #20 102 8 H₂O g. Where was the carbon initially in this chemical reaction and where is it now that it is finished? 2 h. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forward→ Acetyl-CoA + 3NAD+ + 1FAD + 1ADP 2CO2 + CoA + 3NADH + 1FADH2 + 1ATP a. Which of the above are the reactants? b. Which of the above are the products? c. Which reactant is the electron donor? d. Which reactants are the electron acceptors? e. Which of the products are now reduced? f. Which product is now oxidized? g. Which process was used to produce the ATP? h. Where was the energy initially in this chemical reaction and where is it now that it is finished? i. Where was the carbon initially in this chemical reaction and where is it now that it is finished? j. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. OCH 3 (Choose one) OH (Choose one) Br (Choose one) Explanation Check NO2 (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Aarrow_forward
- For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects O donating O withdrawing O no inductive effects Resonance Effects Overall Electron-Density ○ donating ○ withdrawing O no resonance effects O electron-rich O electron-deficient O similar to benzene Cl O donating O withdrawing ○ donating ○ withdrawing O no inductive effects O no resonance effects O Explanation Check O electron-rich O electron-deficient similar to benzene X © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forwardIdentifying electron-donating and For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects NH2 ○ donating NO2 Explanation Check withdrawing no inductive effects Resonance Effects Overall Electron-Density ○ donating O withdrawing O no resonance effects O donating O withdrawing O donating withdrawing O no inductive effects Ono resonance effects O electron-rich electron-deficient O similar to benzene O electron-rich O electron-deficient O similar to benzene olo 18 Ar 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation Check Х (Choose one) OH (Choose one) OCH3 (Choose one) OH (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward
- Assign R or S to all the chiral centers in each compound drawn below porat bg 9 Br Brarrow_forwarddescrive the energy levels of an atom and howan electron moces between themarrow_forwardRank each set of substituents using the Cahn-Ingold-Perlog sequence rules (priority) by numbering the highest priority substituent 1.arrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY