The beaker that has volume triple times of the volume in beaker A is to be identified. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows: N dil = N conc V conc V dil Here, N dil is the number of sphere present in diluted solution. V dil is the volume of diluted solution. N conc the number of sphere present in the concentrated solution. V conc is the volume of concentrated solution.
The beaker that has volume triple times of the volume in beaker A is to be identified. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows: N dil = N conc V conc V dil Here, N dil is the number of sphere present in diluted solution. V dil is the volume of diluted solution. N conc the number of sphere present in the concentrated solution. V conc is the volume of concentrated solution.
The beaker that has volume triple times of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
Vconc is the volume of concentrated solution.
(b)
Interpretation Introduction
Interpretation:
The beaker that has volume double of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
Vconc is the volume of concentrated solution.
(c)
Interpretation Introduction
Interpretation:
The beaker that has volume quadruple of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
You have started a patient on a new drug. Each dose introduces 40 pg/mL of drug after redistribution and prior to elimination. This drug is administered at 24 h intervals and has a half life of 24 h. What will the concentration of drug be after each of the first six doses? Show your work
a. What is the concentration after the fourth dose? in pg/mL
b. What is the concentration after the fifth dose? in pg/mL
c. What is the concentration after the sixth dose? in pg/mL
None
identify the formal charge in the case.
below by indicating the magnitude,
sign, and location of the charge
magnitude and sign of formal charge
location of formal charge (atom
number):
N
Chapter 4 Solutions
Chemistry: The Molecular Nature of Matter and Change
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