(a)
Interpretation:
It should be determined that how many independent material balance may be written for this system.
Concept introduction:
The independent material balance is when the stoichiometric equation of anyone of them can not be obtained by adding or subtracting multiples of the stoichiometric equation of the others.
The material balances are non independent; if two molecular species are in same ratio to each other wherever they appear and if two atomic species are in same ratio to each other wherever they occur.
(b)
Interpretation:
Calculate
Concept introduction:
In order to understand different variables and components of a system, the analysis of degree of freedom can work better. If the degree of freedom is zero then the problem is specified.
The degree of freedom is explained as:
Where, m is total number of independent stream variables, n is number of independent balances, p is total number of specified terms and s is total number of subsidiary relation.
(c)
Interpretation:
Calculate the difference between amount of acetic acid in the feed mixture and that in the 0.5% mixture and show that it equals the amount that leaves in the 9.6% mixture.
Concept introduction:
In any system, for any conserved quantity like total mass, mass of particular species, momentum, energy etc. the balance can be expressed as follows:
Where, input is feed that enters through system boundary, generation is the content produced within system, output is the content which leaves the system and consumption is the feed consumed within the system while accumulation is the actual product build up in the system.
(d)
Interpretation:
Sketch a flow chart of a two-unit process that might be used to recover nearly pure acetic acid from an acetic acid-water mixture.
Concept introduction:
Actually, when a few process information is given and the calculation is to be done on the basis of the information, then in such conditions, flowchart creation is the best way to deal with. It is formed with the help of boxes and arrows to show the process and outline the process units. The arrow lines can show inputs and outputs which help in better understanding of the process.
Learn your wayIncludes step-by-step video
Chapter 4 Solutions
Elementary Principles of Chemical Processes, Binder Ready Version
- At a Pressure of 600 mm Hg, match the substance with the boiling temperature. 54.69°C 1. n-Pentane 49.34°C 2. n-Hexane 3. Acetone 29.32°C く 61.40°C 4. Chloroformarrow_forwardA mixture of oil and gas flows through a horizontal pipe with an inside diameter of 150 mm. The respective volumetric flow rates for the oil and gas are 0.015 and 0.29 m³s-1. Determine the gas void frac- tion and the average velocities of the oil and gas. The friction factor may be assumed to be 0.0045. The gas has a density of 2.4 kgm³ and viscosity of 1 x 10-5 Nsm-2. The oil has a density of 810 kgm³ and density of 0.82 Nsm². Answer: 0.79, 20.8 ms-1, 4 ms-1arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm3. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward
- 1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³. 2. Describe, with the use of sketches, the various flow regimes that can exist in a vertical pipe carrying two-phase flow (liquid and gas).arrow_forwardA mixture of high pressure water and steam at a rate of 0.5 kgs-¹ flows up a vertical tube with an inside diameter of 25.4 mm at a pres- sure 22 bar. Determine the type of flow if the mass quality is 1%. The density of the water is 845 kgm³, the density of steam is 10.8 kgm³, and the viscosity of the water is 1.24 x 104 Nsm2. Answer: Slug flowarrow_forward5. Describe, with the use of sketches, the various two-phase flow regimes that can exist in a horizontal pipe carrying a liquid and a gas. 6. Explain what is meant by gas hold-up and describe ways in which it can be measured.arrow_forward
- A mixture of air and water at a temperature of 25°C flows up through a vertical tube with a length of 4 m and an internal diameter of 25.4 mm with the exit of the tube being at atmospheric pressure. The mass flows of the air and the water are 0.007 kgs¹ and 0.3 kgs-¹, respectively. For air, the density is 1.2 kgm3 and viscosity is 1.85 x 10-5 Nsm-2, and for water, the density is 1000 kgm-3 and viscosity is 8.9 × 10-4 Nsm 2. Answer: 2.7 kNm 2marrow_forwardAt a Pressure of 200 mm Hg, match the substance with the boiling temperature. 69.50°C 1. Benzene 1.92°C 2. Toluene 41.94°C 3. n-Pentane 4. n-Hexane 31.61°Carrow_forwardAt a Pressure of 400 mm Hg, match the substance with the boiling temperature. 62.89°C 1. Styrene 122.69°C 2. Ethanol 3. Toluene 89.48°C 4. Benzene 60.61°Carrow_forward
- 8. A gas is admitted at a rate of 0.015 m³s-¹ to a vertical glass pipe with an inside diameter of 50 mm. The gas bubbles that form travel with a velocity of 32 ms-¹. Determine the gas void fraction and the velocity of the liquid if the volumetric flow is 2.5 x 10-5 m³s-1. Answer: 0.24, 1.7 ms-1 9 Characterise the main concepts of a homogeneous flow model sepa-arrow_forward3. A mixture of air and water at a temperature of 25°C flows up through a vertical tube with a length of 4 m and an internal diameter of 25.4 mm with the exit of the tube being at atmospheric pressure. The mass flows of the air and the water are 0.007 kgs-1 and 0.3 kgs-1, respectively. For air, the density is 1.2 kgm³ and viscosity is 1.85 x 10-5 Nsm-2, and for water, the density is 1000 kgm-3 and viscosity is 8.9 × 10-4 Nsm-2. Answer: 2.7 kNm-2m-1arrow_forward15. Show that for a one-dimensional annular flow in a horizontal pipe with no acceleration, the pressure gradient on the gas core is dp= 4ti dz d√√α where t, is the interfacial shear stress and a is the gas void fraction.arrow_forward
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