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- An electron is a subatomic particle (m accelerates from an initial velocity of +7.54 x 105 m/s to a final velocity of 2.22 x 106 m/s while traveling a distance of 0.0692 m. = 9.11 x 1031 kg) that is subject to electric forces. An electron moving in the +x direction The electron's acceleration is due to two electric forces parallel to the axis: F1 9.04 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2 F, F2 F, on with available attempts. (a) Number Units (b) Number Unitsarrow_forwardAn electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +8.82 x 105 m/s to a final velocity of 1.27 x 106 m/s while traveling a distance of 0.00734 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.63 x 10-¹7 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₂ F₁ (a) Number i (b) Number i Units Units Vo x F₂ F₁arrow_forwardTwo forces F, = -8.40i + 4.30j and F, = 7.50i + 5.30j are acting on an object with a mass of m = 7.80 kg. The forces are measured in newtons, i and j are the unit vectors. What is the magnitude of the object's acceleration? Submit Answer Tries 0/10arrow_forward
- A flea jumps by exerting a force of 1.28 × 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 0.660 x 10-6 N on the flea. Find the direction and magnitude of the acceleration of the flea if its mass is 6.50 x 10-7 kg. Do not neglect the gravitational force. (Assume that the breeze blows in the +x-direction and that the +y-direction is up.) magnitude m/s2 direction o counterclockwise from the +x-axis Additional Materialsarrow_forwardAn electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.88 x 105 m/s to a final velocity of 2.30 x 106 m/s while traveling a distance of 0.0685 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.84 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₂ F₁ VO (a) Number i ! Units N (b) Number Units N eTextbook and Media -> C Σ > F2 F₁ וום 1 0> Assistance Usedarrow_forwardAn electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.88 x 105 m/s to a final velocity of 2.30 x 106 m/s while traveling a distance of 0.0685 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.84 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. (a) Number (b) Number i eTextbook and Media Hint F₂ F₁ ! Units N Units N M ון! > F₁arrow_forward
- An electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.31 x 105 m/s to a final velocity of 1.98 x 106 m/s while traveling a distance of 0.0545 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.52 x 10-¹7 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₁ F₁ F₂ F₁ (a) Number i (b) Number i VO X Units Unitsarrow_forwardA particle of mass 4.00 kg, moving on a horizontal table top, has an acceleration vector (in m/s2) given by a =9.10ı^ + 1.80ȷ^, where ı^ and ȷ^ are the unit vectors along the x and y axes, respectively. This particle is subjected to two horizontal forces, expressed in newtons by F⃗ 1=2.00ı^ + 3.00ȷ^ and F2. Calculate the force F2 in newtons. Give your answer to one decimal placearrow_forwardAn electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.34 x 105 m/s to a final velocity of 1.30 x 106 m/s while traveling a distance of 0.0295 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 9.54 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₂₁ F₂ F₁ (a) Number i (b) Number i Units Units +arrow_forward
- Two forces F, = (81.24i – 26.83ĵ) N and F, = (27.41i - 80.52j) N are exerted on a particle. The particle's mass is 23.21 kg. (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a = m/s2 (b) What are the magnitude and direction of the acceleration? magnitude |x m/s2 direction X ° counterclockwise from the +x axisarrow_forwardUse the value of g = 9.80 [m/s^2]arrow_forwardA 67.3 kg person is standing inside an elevator. The elevator is traveling from the 1st floor to the 8th floor. As the elevator passes the 7th floor it is traveling at a speed of 3.02 m/s and is decelerating at a rate of 1.39 m/s^2. At that moment, what is the net force acting on the person?arrow_forward
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