(a) Answer Gold (III) bromide Explanation Gold has more than one oxidation state. So, binary compound is of type −II. Rules for naming these compounds: Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket. Name of anion is written using root name and adding ‘ide’ to it. Writing these names in the same sequence gives the name of compound. In the formula, A u B r 3 gold is attached to three bromine atoms. It means its oxidation state is three. So the name is Gold (III) bromide. (b) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Cobalt (III) cyanide Explanation Cobalt has more than one oxidation state. So, binary compound is of type −II. Rules for naming these compounds: Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket. Name of anion is written using root name and adding ‘ide’ to it. Writing these names in the same sequence gives the name of compound. In the formula, C o ( C N ) 3 gold is attached to three cyanide ions. It means its oxidation state is three. So the name is Cobalt (III) cyanide. (c) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Magnesium hydrogen phosphate Explanation Magnesium has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion. Rules for naming these compounds: Name of metal cation is written as name of element. Name of anion is written Writing these names in the same sequence gives the name of compound. In the formula, M g H P O 4 magnesium is attached to hydrogen phosphate group. So the name is Magnesium hydrogen phosphate. (d) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Diboron hexahydride Explanation The binary compound is of type −III. Rules for naming these compounds: Type-III: It is name by writing the name of first element as same as element. Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element. In the formula, B 2 H 6 two boron atoms are attached to six hydrogen atoms. So the name is diboron hexahydride. (e) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Nitrogen trihydride or ammonia. Explanation The binary compound is of type −III. Rules for naming these compounds: Type-III: It is name by writing the name of first element as same as element. Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element. In the formula, N H 3 one nitrogen atom is attached to three hydrogen atoms. So the name is Nitrogen trihydride or ammonia. (f) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Silver sulphate Explanation Silver has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion sulphate. Rules for naming these compounds: Name of metal cation is written as name of element. Name of anion is written Writing these names in the same sequence gives the name of compound. In the formula, A g 2 S O 4 silver is attached to sulphate group. So the name is silver sulphate. (g) Interpretation Introduction Interpretation: The name of given compound is to be written. Concept introduction: Binary compounds are of three types: Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions. Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions. Type-III: Compound in which a non-metal forms bond with a non-metal. There is one another type of compound in which metal is bonded with a polyatomic ion. Answer Berrylium hydroxide Explanation Berrylium has one oxidation state. So, binary compound is of type −I. it is combined with hydroxide ion. Rules for naming these compounds: Name of metal cation is written as name of element. Name of anion is written Writing these names in the same sequence gives the name of compound. In the formula, B e ( O H ) 2 berrylium is attached to hydroxide group. So the name is Berrylium hydroxide.

7th Edition

ISBN: 9780618562763

Author: Steven S. Zumdahl

Publisher: Houghton Mifflin College Div

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Question

Chapter 4, Problem 32A

(a)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(a)

Expert Solution

Answer to Problem 32A

Gold (III) bromide

Explanation of Solution

Gold has more than one oxidation state. So, binary compound is of type −II.

Rules for naming these compounds:

Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
Name of anion is written using root name and adding ‘ide’ to it.
Writing these names in the same sequence gives the name of compound.

In the formula, AuBr3 gold is attached to three bromine atoms. It means its oxidation state is three. So the name is Gold (III) bromide.

(b)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(b)

Expert Solution

Answer to Problem 32A

Cobalt (III) cyanide

Explanation of Solution

Cobalt has more than one oxidation state. So, binary compound is of type −II.

Rules for naming these compounds:

Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
Name of anion is written using root name and adding ‘ide’ to it.
Writing these names in the same sequence gives the name of compound.

In the formula, Co(CN)3 gold is attached to three cyanide ions. It means its oxidation state is three. So the name is Cobalt (III) cyanide.

(c)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(c)

Expert Solution

Answer to Problem 32A

Magnesium hydrogen phosphate

Explanation of Solution

Magnesium has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion.

Rules for naming these compounds:

Name of metal cation is written as name of element.
Name of anion is written
Writing these names in the same sequence gives the name of compound.

In the formula, MgHPO4 magnesium is attached to hydrogen phosphate group. So the name is Magnesium hydrogen phosphate.

(d)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(d)

Expert Solution

Answer to Problem 32A

Diboron hexahydride

Explanation of Solution

The binary compound is of type −III.

Rules for naming these compounds:

Type-III:

It is name by writing the name of first element as same as element.
Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element.

In the formula, B2H6 two boron atoms are attached to six hydrogen atoms. So the name is diboron hexahydride.

(e)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(e)

Expert Solution

Answer to Problem 32A

Nitrogen trihydride or ammonia.

Explanation of Solution

The binary compound is of type −III.

Rules for naming these compounds:

Type-III:

It is name by writing the name of first element as same as element.
Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for first element.

In the formula, NH3 one nitrogen atom is attached to three hydrogen atoms. So the name is Nitrogen trihydride or ammonia.

(f)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(f)

Expert Solution

Answer to Problem 32A

Silver sulphate

Explanation of Solution

Silver has one oxidation state. So, binary compound is of type −I. it is combined with polyatomic ion sulphate.

Rules for naming these compounds:

Name of metal cation is written as name of element.
Name of anion is written
Writing these names in the same sequence gives the name of compound.

In the formula, Ag2SO4 silver is attached to sulphate group. So the name is silver sulphate.

(g)

Interpretation Introduction

Interpretation:

The name of given compound is to be written.

Concept introduction:

Binary compounds are of three types:

Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.

Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.

Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion.

(g)

Expert Solution

Answer to Problem 32A

Berrylium hydroxide

Explanation of Solution

Berrylium has one oxidation state. So, binary compound is of type −I. it is combined with hydroxide ion.

Rules for naming these compounds:

Name of metal cation is written as name of element.
Name of anion is written
Writing these names in the same sequence gives the name of compound.

In the formula, Be(OH)2 berrylium is attached to hydroxide group. So the name is Berrylium hydroxide.

Chapter 4, Problem 31A

Chapter 4, Problem 33A

Chapter 4 Solutions

World of Chemistry

Ch. 4.1 - Prob. 1RQ Ch. 4.1 - Prob. 2RQ Ch. 4.1 - Prob. 3RQ Ch. 4.1 - Prob. 4RQ Ch. 4.1 - Prob. 5RQ Ch. 4.1 - Prob. 6RQ Ch. 4.2 - Prob. 1RQ Ch. 4.2 - Prob. 2RQ Ch. 4.2 - Prob. 3RQ Ch. 4.2 - Prob. 4RQ

Ch. 4.2 - Prob. 5RQ Ch. 4.2 - Prob. 6RQ Ch. 4 - Prob. 1A Ch. 4 - Prob. 2A Ch. 4 - Prob. 3A Ch. 4 - Prob. 4A Ch. 4 - Prob. 5A Ch. 4 - Prob. 6A Ch. 4 - Prob. 7A Ch. 4 - Prob. 8A Ch. 4 - Prob. 9A Ch. 4 - Prob. 10A Ch. 4 - Prob. 11A Ch. 4 - Prob. 12A Ch. 4 - Prob. 13A Ch. 4 - Prob. 14A Ch. 4 - Prob. 15A Ch. 4 - Prob. 16A Ch. 4 - Prob. 17A Ch. 4 - Prob. 18A Ch. 4 - Prob. 19A Ch. 4 - Prob. 20A Ch. 4 - Prob. 21A Ch. 4 - Prob. 22A Ch. 4 - Prob. 23A Ch. 4 - Prob. 24A Ch. 4 - Prob. 25A Ch. 4 - Prob. 26A Ch. 4 - Prob. 27A Ch. 4 - Prob. 28A Ch. 4 - Prob. 29A Ch. 4 - Prob. 30A Ch. 4 - Prob. 31A Ch. 4 - Prob. 32A Ch. 4 - Prob. 33A Ch. 4 - Prob. 34A Ch. 4 - Prob. 35A Ch. 4 - Prob. 36A Ch. 4 - Prob. 37A Ch. 4 - Prob. 38A Ch. 4 - Prob. 39A Ch. 4 - Prob. 40A Ch. 4 - Prob. 41A Ch. 4 - Prob. 42A Ch. 4 - Prob. 43A Ch. 4 - Prob. 44A Ch. 4 - Prob. 45A Ch. 4 - Prob. 46A Ch. 4 - Prob. 47A Ch. 4 - Prob. 48A Ch. 4 - Prob. 49A Ch. 4 - Prob. 50A Ch. 4 - Prob. 51A Ch. 4 - Prob. 1STP Ch. 4 - Prob. 2STP Ch. 4 - Prob. 3STP Ch. 4 - Prob. 4STP Ch. 4 - Prob. 5STP Ch. 4 - Prob. 6STP Ch. 4 - Prob. 7STP Ch. 4 - Prob. 8STP Ch. 4 - Prob. 9STP Ch. 4 - Prob. 10STP Ch. 4 - Prob. 11STP

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