World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
Question
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Chapter 4, Problem 27A

(a)

Interpretation Introduction

Interpretation: The formula of the compound containing polyatomic anion is to be given.

Concept Introduction: While writing the formula of a compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(a)

Expert Solution
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Answer to Problem 27A

Formula of compound is Ca3(PO4)2.

Explanation of Solution

Formula of compound is Ca3(PO4)2 as charge on Calcium ion is +2 and that on phosphate ion is -3.

(b)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(b)

Expert Solution
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Answer to Problem 27A

Formula of compound is NH4NO3.

Explanation of Solution

Formula of compound is NH4NO3as charge on Ammonium ion is +1 and that on nitrate ion is -1.

(c)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(c)

Expert Solution
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Answer to Problem 27A

Formula of compound is Al(HSO4)3.

Explanation of Solution

Formula of compound is Al(HSO4)3as charge on Aluminium ion is +3 and that on hydrogen sulfate ion is -1.

(d)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(d)

Expert Solution
Check Mark

Answer to Problem 27A

Formula of compound is BaSO4.

Explanation of Solution

Formula of compound is BaSO4as charge on Barium ion is +2 and that on sulfate ion is -2.

(e)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(e)

Expert Solution
Check Mark

Answer to Problem 27A

Formula of compound is Fe(NO)3.

Explanation of Solution

Formula of compound is Fe(NO)3 as charge on Iron ion is +3 and that on nitrate ion is -1.

(f)

Interpretation Introduction

Interpretation: The formula of the binary ionic compound is to be given.

Concept Introduction: While writing the formula of an ionic compound, cation is written first followed by anion. Also the charge on the ions is taken into account. The charge on cation becomes subscript of anion and vice-versa.

(f)

Expert Solution
Check Mark

Answer to Problem 27A

Formula of compound is CuOH.

Explanation of Solution

Formula of compound is CuOH as charge on Copper ion is +1 and that on hydroxide ion is -1.

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Chapter 4, Problem 26A
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Chapter 4, Problem 28A

Chapter 4 Solutions

World of Chemistry

Ch. 4.1 - Prob. 1RQCh. 4.1 - Prob. 2RQCh. 4.1 - Prob. 3RQCh. 4.1 - Prob. 4RQCh. 4.1 - Prob. 5RQCh. 4.1 - Prob. 6RQCh. 4.2 - Prob. 1RQCh. 4.2 - Prob. 2RQCh. 4.2 - Prob. 3RQCh. 4.2 - Prob. 4RQ
Ch. 4.2 - Prob. 5RQCh. 4.2 - Prob. 6RQCh. 4 - Prob. 1ACh. 4 - Prob. 2ACh. 4 - Prob. 3ACh. 4 - Prob. 4ACh. 4 - Prob. 5ACh. 4 - Prob. 6ACh. 4 - Prob. 7ACh. 4 - Prob. 8ACh. 4 - Prob. 9ACh. 4 - Prob. 10ACh. 4 - Prob. 11ACh. 4 - Prob. 12ACh. 4 - Prob. 13ACh. 4 - Prob. 14ACh. 4 - Prob. 15ACh. 4 - Prob. 16ACh. 4 - Prob. 17ACh. 4 - Prob. 18ACh. 4 - Prob. 19ACh. 4 - Prob. 20ACh. 4 - Prob. 21ACh. 4 - Prob. 22ACh. 4 - Prob. 23ACh. 4 - Prob. 24ACh. 4 - Prob. 25ACh. 4 - Prob. 26ACh. 4 - Prob. 27ACh. 4 - Prob. 28ACh. 4 - Prob. 29ACh. 4 - Prob. 30ACh. 4 - Prob. 31ACh. 4 - Prob. 32ACh. 4 - Prob. 33ACh. 4 - Prob. 34ACh. 4 - Prob. 35ACh. 4 - Prob. 36ACh. 4 - Prob. 37ACh. 4 - Prob. 38ACh. 4 - Prob. 39ACh. 4 - Prob. 40ACh. 4 - Prob. 41ACh. 4 - Prob. 42ACh. 4 - Prob. 43ACh. 4 - Prob. 44ACh. 4 - Prob. 45ACh. 4 - Prob. 46ACh. 4 - Prob. 47ACh. 4 - Prob. 48ACh. 4 - Prob. 49ACh. 4 - Prob. 50ACh. 4 - Prob. 51ACh. 4 - Prob. 1STPCh. 4 - Prob. 2STPCh. 4 - Prob. 3STPCh. 4 - Prob. 4STPCh. 4 - Prob. 5STPCh. 4 - Prob. 6STPCh. 4 - Prob. 7STPCh. 4 - Prob. 8STPCh. 4 - Prob. 9STPCh. 4 - Prob. 10STPCh. 4 - Prob. 11STP
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