Chapter 4, Problem 29A

(a)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $LiCl$

Explanation of Solution

Lithium chloride is a compound of metal of type-I with non-metal chlorine. Lithium ion carries +1 charge and chloride carries -1. So, to make net charge zero one ion of Lithium is joined with one chloride ion. Therefore, correct formula is $LiCl$ .

(b)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $C{u}_{2}C{O}_3$

Explanation of Solution

Cuprous carbonate is a compound of metal of type-II with polyatomic ion. Cuprous ion carries +1 charge and carbonate ion carries -2. So, to make net charge zero two ions of copper is joined with one carbonate ion. Therefore, correct formula is $C{u}_{2}C{O}_3$ .

(c)

Interpretation Introduction

Interpretation:

The formula for given compound is to be written.

Concept introduction:

An acid is a substance which give hydrogen ion or proton in solution.

Answer to Problem 29A

  $HBr$

Explanation of Solution

The name hydrobromic acid shows acid of bromine. As bromine forms one covalent bond with hydrogen. So, the formula is $HBr$ .

(d)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $Ca{\left(N{O}_3\right)}_2$

Explanation of Solution

Calcium nitrate is a compound of metal of type-I with polyatomic ion. Calcium ion carries +2 charge and nitrate carries -1. So, to make net charge zero one ion of calcium is joined with two nitrate ions. Therefore, correct formula is $Ca{\left(N{O}_3\right)}_2$ .

(e)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $NaCl{O}_4$

Explanation of Solution

Sodium perchlorate is a compound of metal of type-I with polyatomic ion. Sodium ion carries +1 charge and perchlorate carries -1. So, to make net charge zero one ion of sodium is joined with one perchlorate ion ( $Cl{O}_4{}^{-}$ ). Therefore, correct formula is $NaCl{O}_4$ .

(f)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $Al{\left(OH\right)}_3$

Explanation of Solution

Aluminium hydroxide is a compound of metal of type-I with polyatomic ion. Aluminium ion carries +3 charge and hydroxide ion carries -1. So, to make net charge zero one ion of aluminium is joined with three hydroxide ions. Therefore, correct formula is $Al{\left(OH\right)}_3$ .

(g)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $Ba{\left(HC{O}_3\right)}_2$

Explanation of Solution

Barium hydrogen carbonate is a compound of metal of type-I with polyatomic ion. Barium ion carries +2 charge and hydrogen carbonate carries -1. So, to make net charge zero one ion of barium is joined with two hydrogen carbonate ions ( $HC{O}_3{}^{-}$ ). Therefore, correct formula is $Ba{\left(HC{O}_3\right)}_2$ .

(h)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

1. Name of metal cation is written as name of element.
2. Name of anion is written using root name and adding ‘ide’ to it.
3. Writing these names in the same sequence gives the name of compound.

Type-II:

1. Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
2. Name of anion is written using root name and adding ‘ide’ to it.
3. Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $FeS{O}_4$

Explanation of Solution

Iron (II) sulfate is a compound of metal of type-II with polyatomic ion. Iron ion carries +2 charge signified by roman numeral and sulphate carries -2. So, to make net charge zero one ion of iron is joined with one sulfate ion. Therefore, correct formula is $FeS{O}_4$ .

(i)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $B_{2}C{l}_6$

Explanation of Solution

Diboron hexachloride is a compound of non-metal with non-metal. So, applying the rules, two boron atoms are attached with six chlorine atoms. Therefore, correct formula is $B_{2}C{l}_6$ .

(j)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $PB{r}_5$

Explanation of Solution

Phosphorus pentabromide is a compound of non-metal with non-metal. So, applying the rules, phosphorus atom is attached with five bromine atoms. Therefore, correct formula is $PB{r}_5$ .

(k)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $KS{O}_3$

Explanation of Solution

Potassium sulfite is a compound of metal of type-I with polyatomic ion. Potassium ion carries +1 charge and sulpfite carries -1. So, to make net charge zero one ion of potassium is joined with one sulfite ion ( $S{O}_3{}^{-}$ ). Therefore, correct formula is $KS{O}_3$ .

(l)

Interpretation Introduction

Interpretation:

The formula of given compound is to be written.

Concept introduction:

To name a compound, certain rules are followed. The given compounds are binary compounds.

Binary compounds are of three types:

• Type-I: Compound in which a metal forms ionic bond with a non-metal and the metal can form only one type of ions.
• Type-II: Compound in which a metal forms ionic bond with a non-metal and the metal can form more than one type of ions.
• Type-III: Compound in which a non-metal forms bond with a non-metal.

There is one another type of compound in which metal is bonded with a polyatomic ion

Rules for naming these compounds:

Type-I:

• Name of metal cation is written as name of element.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-II:

• Name of metal cation is written as name of element followed by charge carried by it in roman numerals in bracket.
• Name of anion is written using root name and adding ‘ide’ to it.
• Writing these names in the same sequence gives the name of compound.

Type-III:

• It is name by writing the name of first element as same as element.
• Second element in anionic form and prefixes are used to denote the number of atoms. Prefix mono is not used for one element.

When metal is bonded with polyatomic ion, rules are similar to ionic binary compounds.

Answer to Problem 29A

  $Ba{\left(C{H}_{3}COO\right)}_2$

Explanation of Solution

Barium acetate is a compound of metal of type-I with polyatomic ion. Barium ion carries +2 charge and acetate carries -1. So, to make net charge zero one ion of barium is joined with two acetate ions ( $C{H}_{3}CO{O}^{-}$ ). Therefore, correct formula is $Ba{\left(C{H}_{3}COO\right)}_2$ .